Question

Evaluate the expression for the given values of the variables. $$ (x+y)^{2} \text { when } x=5 \text { and } y=3 $$

Short answer

The value of the expression \((x+y)^{2}\) when \(x = 5\) and \(y = 3\) is 64.

Step-by-step solution

Substitution

Replace the \(x\) and \(y\) in the equation \((x+y)^{2}\) with the given values. This will give: \((5+3)^{2}\).

Perform the Addition Operation

Perform the addition operation inside the parentheses before squaring. The equation becomes: \(8^2\).

Perform the Squaring Operation

Now square the result from the previous step: \(8^2 = 64\).