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(Cauchy’s Theorem for Abelian groups) If is a finite abelian group and is a prime that divides , prove that contains an element of order .[Hint: Use the Fundamental Theorem to show that has a cyclic subgroup of order ; use Theorem 7.9 to find an element of order .]

Short Answer

Expert verified

It is proved that, Gcontains an element of order p.

Step by step solution

01

Fundamental Theorem and Theorem 7.2,7.9

Every finite abelian group G is the direct sum of cyclic groups, each of prime power orders.

Theorem 7.2 states that the non-zero elements of a field form an abelian group under multiplication.

Theorem 7.9 states that be a group and an element of finite order n then,

1. role="math" localid="1657297632189" ak=eif and only if role="math" localid="1657297673488" nk.

2. ai=ajif and only if ij(modn).

3.If n=td, with d1 then at has order d.

02

  contains element of order  

Let Gbe a finite abelian group and pbe a prime that divides Gthat is pG, .

By Fundamental Theorem of abelian group, there exists an element kZand a subgroup Hof Gsuch that, GZpkH .

Thus, for aG,a=pk. Since aG implies ppk then, the order of a can be written asapk-1=p

Here, the element apk-1G has order p.

Therefore, if Gis a finite abelian group and p is a prime that dividesG , then G contains an element of order p.

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