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Question 4: Let [a]ndenote the congruence class of the integer a modulon .

(b) Find the kernel off .

Short Answer

Expert verified

The kernel of f is412

Step by step solution

01

Definition of kernel

Letf:RS be a homomorphism of rings. Then, the kernel off is the set

K={rR|fr=0S}.

02

Definition of f

Here,f:124 that sendsa12 to a4.

Since fis a well-defined surjective homomorphism, so we can directly say that kernel of fis ideal generated by 412.

03

Conclusion

So, the Kernel off is412={012,412,812}.

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