Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

(a) If (a1,a2,...) and(b1,b2,...) are polynomials, show that their sum is a polynomial (that is, after some point all coordinates of the sum are zero).

(b) Show thatrole="math" localid="1658910018438" (a1,a2,...)(b1,b2,...) is a polynomial.

Short Answer

Expert verified
  1. The addition of given two polynomial is P(x1+x2)=(a1+b1)+(a2+b2)x.
  2. It is shown that (a1,a2,...)(b1,b2,...)is a polynomial.

Step by step solution

01

Introduction of polynomial 

Consider the polynomial in xand will be express as;

role="math" localid="1658910328362" P(x)=a0x0+a1x1+a2x2+...+anxn

Polynomial is always finite but sequence can be finite and infinite.

02

Show that the sum of (a1, a2,...) and (b1, b2,...) is a polynomial 

(a)

Consider the sequences (a1,a2,...)and (b1,b2,...)are the polynomials then the polynomial for the sequence (a1,a2,...)is,

P(x1)=a1x0+a2x1+0x2+0x3+0x4=a1+a2x

For the sequence,(b1,b2,...) the polynomials is,

P(x2)=b1x0+b2x1+0x2+0x3+0x4=b1+b2x

Add the above two sequences.

(a1,a2,0,0,0,...)+(b1,b2,0,0,0,...)=(a1+b1,a2+b2,0,0,0,...)

The polynomial for the sequence(a1+b1,a2+b2,0,0,0,...) is,

role="math" localid="1658910585116" P(x1+x2)=(a1+b1)x0+(a2+b2)x1=(a1+b1)+(a2+b2)x

Therefore, the addition of given two polynomial isP(x1+x2)=(a1+b1)+(a2+b2)x .

03

Show that (a1, a2,...)⊙(b1, b2,...) is a polynomial

(b)

Consider the sequences (a1,a2,...)and (b1,b2,...), these two sequence is infinite sequences of a finite coefficients of a polynomial.

So, the rest entries of the polynomial will be zeroes because polynomial will never be infinite.

Therefore, the sequence will be as follows.

(a1,a2,0,0,0,...)and (b1,b2,0,0,0,...),

Evaluate (a1,a2,...)(b1,b2,...).

(a1,a2,...)(b1,b2,...)=(a1b1,a1b2,a2b1,a2b2,0,0,0,...)

The polynomial for the sequencerole="math" localid="1658910793522" (a1b1,a1b2,a2b1,a2b2,0,0,0,...) will be as follows.

P(x)=(a1b1)x0+(a1b2)x1+(a2b1)x2+(a2b2)x3+0x4+0x5+0x6=(a1b1)+(a1b2)x+(a2b1)x2+(a2b2)x3

Therefore, (a1,a2,...)(b1,b2,...)is a polynomial.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free