Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

In the set [x]of all polynomials with real coefficients define f(x)~g(x)if and only if f'(x)=g'(x), where ‘ denotes the derivative. Prove that~is an equivalence relation on[x].

Short Answer

Expert verified

We proved that~ is an equivalence relation.

Step by step solution

01

To mention given data

Let ~be defined on [x]by:

localid="1659174882722" f(x)~g(x)if and only if f'x=g'x.

We have to prove that ~is an equivalence relation.

In order to prove that~is an equivalence relation, we need to prove the following conditions:

  1. ~’ is reflexive.
  2. ~’ is symmetric.
  3. ~’ is transitive.
02

To prove that ~ is reflexive

Let f(x)[x].

The,

f(x)~f(x)f'(x)=f'(x)

Hence,~is reflexive.

03

To prove that ~ is symmetric

Letf(x),g(x)[x].

Then suppose that

f(x)~g(x)f'(x)=g'(x)g'(x)=f'(x)g(x)~f(x)

Hence,~is symmetric.

04

To prove that ~ is transitive

Letf(x),g(x),h(x)[x].

Then suppose that

f(x)~g(x),g(x)~h(x)f'(x)=g'(x),g'(x)=h'(x)f'(x)=h'(x)f(x)~h(x)


Hence, ~is transitive.

Hence, ~is an equivalence relation since all the conditions are satisfied.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

At a social bridge party every couple plays every other couple exactly once. Assume there are no ties.

  1. Ifcouples participate, prove that there is a “best couple” in the following sense: A couple uis “best” provided that for every couple v, ubeats vor ubeats a couple that beats v.
  2. Show by an example that there may be more than one best couple.

What is wrong with the following "proof" that all roses are the same color. It suffices to prove the statement: In every set of n roses, all the roses in

the set are the same color. If n = 1, the statement is certainly true. Assume

the statement is true for n = k. Let S be a set of k + 1 roses. Remove one

rose (call it rose A) from S; there are k roses remaining, and they must all

be the same color by the induction hypothesis. Replace rose A and remove

a different rose (call it rose B). Once again there are k roses remaining that

must all be the same color by the induction hypothesis. Since the remaining

roses include rose A, all the roses in Shave the same color. This proves that

the statement is true when n = k + 1. Therefore, the statement is true for all

n by induction.

Question: Let r and n be integers with 0 < r < n. Prove that[nr]=[nn-r].

Prove that f:BCis injective if and only iff(SIT)=f(S)If(T) for every pair of subsets S,T of .

Let B be set of n elements.

(a) If n2, prove that the number of two –element subsets of B is n(n-1)2.

(b) If n3, prove that the number of three –element subsets of is n(n-1)(n-2)3!.

(c) Make a conjecture as to the number of K - elements subsets of B when nk. Prove your conjecture.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free