Question

. Show that the total length of the parallel at latitude \(\alpha\) equals \(\cos \alpha\) multiplied by the total length of the equator.

Short answer

Question: Show that the length of a parallel at latitude α is given by the product of cos(α) and the total length of the equator. Answer: The length of a parallel at latitude α is equal to the product of cos(α) and the total length of the equator, as proven by the equation \(\frac{L_\alpha}{L_{eq}} = \cos \alpha\).

Step-by-step solution

Write down the formula for the length of a parallel

The length of a parallel at latitude α on a sphere with radius R can be calculated using the formula: Parallel length (\(L_\alpha\)) = \(2 \pi R \cos \alpha\)

Write down the formula for the length of the equator

The equator is the largest circle on a sphere and is a special case of a parallel at latitude 0. The length of the equator can be calculated using the same formula as for other parallels: Equator length (\(L_{eq}\)) = \(2 \pi R\)

Divide parallel length by equator length

Now, we will divide the length of a parallel at latitude α by the length of the equator: \(\frac{L_\alpha}{L_{eq}} = \frac{2 \pi R \cos \alpha}{2 \pi R}\)

Simplify the equation and prove the statement

After dividing the two formulas, notice that the \(2\pi R\) terms cancel out. This results in the following equation: \(\frac{L_\alpha}{L_{eq}} = \cos \alpha\) This equation proves that the total length of a parallel at latitude α is equal to the product of cos(α) and the total length of the equator.

Key concepts

Latitude in Mathematics

In mathematics, and more specifically in spherical geometry, latitude is a measure of position on Earth or any spherical body. It is an angle that ranges from 0° at the Equator to 90° at the poles. Latitudes are parallel circles on the surface of the Earth, with the size of each circle decreasing as one moves from the Equator towards the poles.

Imagine slicing the Earth into horizontal slices. Each slice represents a circle, known as a parallel. Parallels at higher latitudes are smaller, and the relationship between the size of these circles and their latitude is where cosine comes into play. Due to the spherical shape, as you move along these parallels from the equator, the radius of the circle decreases proportionally to the cosine of the latitude angle, reflecting the three dimensional geometry of a sphere.

Circumference of a Sphere

The circumference of a sphere is an essential concept in understanding spherical geometry. It's the distance around the largest circle that can be drawn on a sphere, which is found at the equator. To find the circumference of a sphere, we use the well-known formula:

\[C = 2 \times \text{π} \times R\]

where \(C\) is the circumference, \(\text{π}\) (pi) is a constant approximately equal to 3.14159, and \(R\) is the radius of the sphere. This formula is crucial because it allows us to explore the relationships between circles at different latitudes. By understanding how the equatorial circumference relates to other parallels, we can see the practical applications, such as in calculating distances and areas on Earth's surface.

Trigonometric Functions in Geometry

Trigonometric functions are the bridge between angular and linear measurements in geometry, allowing us to transition from angles to distances. They are especially useful in spherical geometry, where angles define positions on the sphere, and trigonometry provides the means to calculate distances.

In the context of the given exercise, the cosine function is instrumental. It is defined for a right-angled triangle as the ratio of the adjacent side to the hypotenuse:

\[ \text{cosine}(\text{angle}) = \frac{\text{adjacent side}}{\text{hypotenuse}}\]

When dealing with spheres, we use trigonometric functions to relate the latitude angle to the corresponding parallel's length. By understanding how to incorporate trigonometry into our calculations, such as using cosine to find the length of a parallel at latitude \(\alpha\), we enhance our ability to navigate and understand the spherical world around us.