Chapter 24: Problem 2
Show that if a surface is given in the form \(z=z(x, y)\), then the measure of curvature \(k\) can be expressed as $$ k=\frac{z_{x x} z_{y y}-z_{x y}^{2}}{\left(1+z_{x}^{2}+z_{y}^{2}\right)^{2}} $$ Hint: Show first that if \(X, Y, Z\) are coordinates on the unit sphere corresponding to the point \((x, y, z(x, y))\) on the given surface, then $$ \begin{aligned} &X=\frac{-z_{x}}{\sqrt{1+z_{x}^{2}+z_{y}^{2}}}, \quad Y=\frac{-z_{y}}{\sqrt{1+z_{x}^{2}+z_{y}^{2}}} \\ &Z=\frac{1}{\sqrt{1+z_{x}^{2}+z_{y}^{2}}} \end{aligned} $$
Short Answer
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Key Concepts
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