Derive Johann Bernoulli's differential equation for the catenary, \(d y / d x=s
/ a\), as follows: Let the lowest point of the hanging cord be the origin of
the coordinate system, and consider a piece of the chord of length \(s\) over
the interval into a closed-form expression. \([0, x]\). Let \(T(x)\) be the
(vector) tension of the cord at the point \(P=(x, y)\). Let \(\alpha\) be the
angle that \(T(x)\) makes with 3. Derive Johann Bernoulli's differential
equation for the the horizontal and let \(\rho\) be the density of the cord.
Show that the equilibrium of horizontal forces gives the equation. equation \(d
s=\frac{\sqrt{a} d y}{\sqrt{x}}\) \(|T(0)|=|T(x)| \cos \alpha\), while that of
the vertical forces gives \(\rho s=|T(x)| \sin \alpha .\) Since \(d y / d x=\tan
\alpha\), Bernoulli's equaDapro tion can be derived by dividing the second
equation by the differences of the parts is equal to the difference of the
sums first. of the parts.