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Solve by the method of false position: A quantity and its \(1 / 7\) added together become 19. What is the quantity? (problem 24 of the Rhind Mathematical Papyrus)

Short Answer

Expert verified
Answer: The approximate quantity of x is 11.79.

Step by step solution

01

Set up the equation

First, we need to write the problem as an equation. Let x be the quantity. Then, the given statement can be translated into the equation: $$x + \frac{1}{7}x = 19$$
02

Choose a false position

Let's choose a random value as a false position, which we will later utilize to adjust our value of x accordingly. Let's choose 14 as our false position value for x, assuming that the proportion to the correct value remains constant.
03

Plug in the false position value

Now, plug in the false position value of 14 into the equation: $$14 + \frac{1}{7}(14) = 14 + 2 = 16$$
04

Find the proportion

We now find what proportion the result (16) is of the actual total (19) to adjust our assumed value (14) accordingly: $$\frac{16}{19} = \frac{x}{14}$$
05

Solve for x

Cross-multiply and solve the equation for x: $$16 \times 14 = 19 \times x \Rightarrow x = \frac{16 \times 14}{19}$$
06

Calculate x

Multiply and simplify the fraction to find the value of x: $$x = \frac{16 \times 14}{19} = \frac{224}{19} = 11.79$$ The approximate quantity x is 11.79.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rhind Mathematical Papyrus
The Rhind Mathematical Papyrus is one of the earliest known sources of Egyptian mathematics, dating to around 1550 BC. It's named after the Scottish Egyptologist Alexander Henry Rhind, who purchased the papyrus in 1858. This ancient document provides a fascinating glimpse into the mathematical understanding of the Egyptians, featuring arithmetic, geometry, and algebraic problems similar to the one presented in our exercise.

The papyrus contains around 84 different mathematical problems, providing us with insight into how Egyptians approached problem-solving, notably using the method of false position to solve linear equations. Studying problems from the Rhind Mathematical Papyrus, like the one about finding a quantity with its fraction that sums up to a specific total, shows us the historical roots of algebra and the methods that lead to the mathematical principles we use today.
Mathematical Problem-Solving
Mathematical problem-solving is a fundamental skill that allows us to find solutions to various types of mathematical questions. It involves understanding the problem, devising a plan, carrying out that plan, and then checking the results. Steps such as these are integral to tackling any mathematical challenge.

Methods like the one in our textbook exercise, the method of false position, are foundational techniques in problem-solving strategies. By using a trial-and-error approach, and then adjusting proportionally based on the false attempt, students learn to navigate towards the correct solution. This technique is not only historically significant but also immensely practical, teaching a logical approach to problem-solving that can be applied beyond mathematics.
Historical Mathematics
Historical mathematics reveals the evolution of mathematical thought throughout the ages and across different cultures. From Babylonian tablets to Greek geometry, and from the mathematical advancements in ancient India to the contributions of Islamic scholars during the middle ages, each culture added to the collective understanding of math.

Studying the historical context of mathematical development, such as the use of the method of false position from the Rhind Mathematical Papyrus, underlines the continuity and progression of mathematical thinking. It highlights the ingenuity of ancient mathematicians who developed methods that remain relevant. The exchange of mathematical ideas over time and geography has been instrumental in creating the diverse field of mathematics we know today.
Algebraic Equations
Algebraic equations are the cornerstone of algebra and serve as a fundamental component of modern mathematics. They consist of mathematical statements that showcase a relationship between quantities, often involving variables and constants, where the values of the variables must be determined.

The method of false position, as shown in the textbook exercise, is an ancient technique to solve linear algebraic equations. It requires an initial guess which is then refined to reach the solution. This method represented a significant advance in algebraic thinking and contributed to the development of equations as we know them. Equations are now used to describe everything from simple relationships to complex systems in various fields such as science, finance, and engineering.

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Most popular questions from this chapter

The scribe of Plimpton 322 did not use the value \(v+\) \(u=2 ; 18,14,24\), with its associated reciprocal \(v-u=\) \(0 ; 26,02,30\), in his work on the tablet. Find the smallest Pythagorean triple associated with those values.

Show that the solution to the problem of dividing 7 loaves among 10 men is that each man gets \(\overline{\overline{3}} \overline{30}\). (This is problem 4 of the Rhind Mathematical Papyrus.)

Solve the following Babylonian problem about a concave square: The sum of the area, the arc, and the diagonal is \(1 ; 16,40\left(=1 \frac{5}{18}\right) .\) Find the length of the arc. (Recall that the coefficient of the area is \(4 / 9\) and the coefficient of the diagonal is \(11 / 3\)-see Exercise 23.)

Solve the following problem from tablet AO 8862: Length and width. I combined length and width and then I built an area. I turned around. I added half of the length and a third of the width to the middle of my area so that it was \(15 . \mathrm{I}\). returned. I summed the length and width and it was 7 . What are the length and width?

Problem 72 of the Rhind Mathematical Papyrus reads " 100 loaves of pesu 10 are exchanged for loaves of pesu 45 . How many of these loaves are there? The solution is given as, "Find the excess of 45 over \(10 .\) It is 35 . Divide this 35 by 10. You get \(3 \overline{2}\). Multiply \(3 \overline{2}\) by 100. Result: 350. Add 100 to this 350 . You get 450 . Say then that the exchange is 100 loaves of pesu 10 for 450 loaves of pesu \(45 . "^{18}\) Translate this solution into modern terminology. How does this solution demonstrate proportionality?

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