Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Let \(U\) be gamma distributed with order \(p\) and let \(V\) have the beta distribution with parameters \(q\) and \(p-q(0

Short Answer

Expert verified
The detailed calculations result in an expression that matches the gamma distribution with order \(q\), as was to be shown.

Step by step solution

01

Identify the Double Integral

Start with the given double integral \[\operatorname{Pr}\{U V \leq x\}=\int_{0}^{1}\left(\int_{0}^{x / \xi} e^{-\lambda} \lambda^{p-1} d \lambda\right) \frac{\xi^{q-1}(1-\xi)^{p-q-1} d \xi}{\Gamma(q) \Gamma(p-q)} \] This represents the probability that the product \(U V\) is less than or equal to a certain value \(x\).
02

Apply Laplace Transform

Apply the Laplace transform to both sides of the equation. This is defined for a function \(f(t)\) by \[L\{f(t)\}=\int_{0}^{\infty}e^{-st}f(t)dt \] where \(s\) is a complex number.
03

Interchange the Order of Integration

Next, interchange the order of integration in the double integral. In general, this can be done if the region of integration is a rectangle and if the integrand is continuous.
04

Use Binomial Expansion

Use the binomial series expansion \[(1+y)^{-z-1}=\sum_{k=0}^{\infty}\left(\begin{array}{c} \alpha+k \ k \end{array}\right) y^{k} \] to handle the integral. Here \(y\) and \(z\) are any numbers, and \[\left(\begin{array}{c} \alpha+k \ k \end{array}\right) \] is a binomial coefficient.
05

Identify the Gamma Distribution

After performing these calculations, the aim is to match the resulting integral expression with the known form of the gamma distribution. This is a process of pattern matching and knowing the analytic forms of these distributions.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Suppose we have \(N\) chips, numbered \(1,2, \ldots, N .\) We take a random sample of size \(n\) without replacement. Let \(X\) be the largest number in the random sample. Show that the probability function of \(X\) is $$ \operatorname{Pr}\\{X=k\\}=\frac{\left(\begin{array}{l} k-1 \\ n-1 \end{array}\right)}{\left(\begin{array}{c} N \\ n \end{array}\right)} \quad \text { for } k=n, n+1, \ldots, N $$ and that $$ E X=\frac{n}{n+1}(N+1), \quad \operatorname{Var}(X)=\frac{n(N-n)(N+1)}{(n+1)^{2}(n+2)} $$

Consider an infinite number of urns into which we toss balls independently, in such a way that a ball falls into the \(k\) th urn with probability \(1 / 2^{k}, k=1,2,3\). \(\ldots .\) For each positive integer \(N\), let \(Z_{N}\) be the number of urns which contain at least one ball after a total of \(N\) balls have been tossed. Show that $$ E\left(Z_{N}\right)=\sum_{\lambda=1}^{\infty}\left[1-\left(1-1 / 2^{k}\right)^{N}\right] $$ and that there exist constants \(C_{1}>0\) and \(C_{2}>0\) such that $$ C_{1} \log N \leq E\left(Z_{N}\right) \leq C_{2} \log N \quad \text { for all } N $$ Hint: Verify and use the facts: $$ E\left(Z_{N}\right) \geq \sum_{k=1}^{\log _{2}-N}\left[1-\left(1-\frac{1}{2^{k}}\right)^{N}\right] \geq C \log _{2} N $$ and $$ 1-\left(1-\frac{1}{2^{k}}\right)^{N} \leq N \frac{1}{2^{k}} \text { and } N \sum_{\log _{2}}^{\infty} \frac{1}{2^{k}} \leq C_{2} $$

Let \(X\) be a nonnegative random variable with cumulative distribution funetion \(F(x)=\operatorname{Pr}\\{X \leq x\\}\). Show $$ E[X]=\int_{0}^{\infty}[1-F(x)] d x $$ Hint: Write \(E[X]=\int^{\infty} x d F(x)=\int^{\infty}\left(\int_{0}^{x} d y\right) d F(x)\).

The random variables \(X\) and \(Y\) have the following properties: \(X\) is positive, i.e., \(P\\{X>0\\}=1\), with continuous density funetion \(f(x)\), and \(Y \mid X\) has a uniform distribution on \(\\{0, X\\} .\) Prove: If \(Y\) and \(X-Y\) are independently dis* tributed, then $$ f(x)=a^{2} x e^{-a x}, \quad x>0, \quad a>0 $$

Suppose that a lot consists of \(m, n_{1}, \ldots, n_{r}\), items belonging to the \(0 \mathrm{th}\), (1n1,..., \(r\) th classes respeetively. The items are drawn one-by-one without replace. ment until \(k\) items of the 0 th elass are observed. Show that the joint aistribution of the observed frequencies \(X_{1}, \ldots, X_{r}\) of the Ist,..., \(r\) th classes is $$ \begin{gathered} \operatorname{Pr}\left\\{X_{1}=x_{1}, \ldots, X_{r}=x_{r}\right\\}=\left\\{\left(\begin{array}{c} m \\ k-1 \end{array}\right) \prod_{i=1}^{r}\left(\begin{array}{l} n_{i} \\ x_{i} \end{array}\right) /\left(\begin{array}{c} m+n \\ k+y-1 \end{array}\right)\right\\} \\ \cdot \frac{m-(k-1)}{m+n-(k+y-1)} \end{gathered} $$ where $$ y=\sum_{i=1}^{r} x_{1} \quad \text { and } \quad n=\sum_{i=1}^{r} n_{i^{*}} $$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free