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If X is a binomial random variable with expected value 6and variance2.4, find P{X=5}

Short Answer

Expert verified

P(X=5)=0.2

Step by step solution

01

Step 1: Given information

Given in the question that,Xis a binomial random variable with expected value6and variance 2.4,

02

Step 2: Explanation

We have that X~Binom(n,p).

We are given informations

EX=6np=6

Var(X)=2.4np(1-p)=2.4

Dividing the second equation with the first one, we end up with equation 1-p=2.46=0.4, so we have that p=0.6. Hence, we also have that n=10.

Finally, we are required to determine following

P(X=5)=1050.650.45=0.2

03

Step 3: Final answer

P(X=5)=0.2

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Most popular questions from this chapter

Find Var(X) and Var(Y) for X and Y as given in Problem 4.21

Suppose that the average number of cars abandoned weekly on a certain highway is 2.2. Approximate the probability that there will be

(a) no abandoned cars in the next week;

(b) at least abandoned cars in the next week.

The suicide rate in a certain state is 1 suicide per 100,000 inhabitants per month.

(a) Find the probability that in a city of 400,000 inhabitants within this state, there will be 8 or more suicides in a given month.

(b) What is the probability that there will be at least 2 months during the year that will have 8 or more suicides?

(c) Counting the present month as month number 1, what is the probability that the first month to have 8 or more suicides will be month number i,i1? What assumptions are you making?

There are three highways in the county. The number of daily accidents that occur on these highways are Poisson random variables with respective parameters .3,.5,and .7. Find the expected number of accidents that will happen on any of these highways today.

Here is another way to obtain a set of recursive equations for determining Pn, the probability that there is a string of kconsecutive heads in a sequence of nflips of a fair coin that comes up heads with probability p:

(a) Argue that for k<n, there will be a string of kconsecutive heads if either

1. there is a string of kconsecutive heads within the first n-1flips, or

2. there is no string of kconsecutive heads within the first n-k-1flips, flip n-kis a tail, and flips n-k+1,,nare all heads.

(b) Using the preceding, relate PntoPn-1. Starting with Pk=pk, the recursion can be used to obtain Pk+1, thenPk+2, and so on, up to Pn.

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