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Repeat Theoretical Exercise 4.32, this time assuming that withdrawn chips are not replaced before the next selection.

Short Answer

Expert verified

Probability mass function does not exist

Step by step solution

01

Given information

Jar contains nchips

Withdrawn chips are not replaced before the next selection

X= number of draws until previously drawn chip is drawn again

02

Explanation

When the chips are not replaced before the next selection, then it is not possible to draw a previously drawn chip again.

This then implies that Xis not a random variable, because all integer values for Xcannot be an outcome for Xand thus the value of Xis not random.

03

Final answer

Since X is not a random variable, the probability mass function of X does not exist.

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Most popular questions from this chapter

There are ktypes of coupons. Independently of the types of previously collected coupons, each new coupon collected is of typeiwith probability pi, i=1kpi=1. If n coupons are collected, find the expected number of distinct types that appear in this set. (That is, find the expected number of types of coupons that appear at least once in the set of ncoupons.)

Suppose that the number of accidents occurring on a highway each day is a Poisson random variable with parameter λ = 3.

(a) Find the probability that 3 or more accidents occur today.

(b) Repeat part (a) under the assumption that at least 1 accident occurs today.

There are N distinct types of coupons, and each time one is obtained it will, independently of past choices, be of type i with probability Pi, i = 1, ... , N. Let T denote the number one need select to obtain at least one of each type. Compute P{T = n}.

Compare the Poisson approximation with the correct binomial probability for the following cases:

(a)P{X=2}whenn=8,p=.1;

(b)P{X=9}whenn=10,p=.95;

(c)P{X=0}whenn=10,p=.1;

(d) P{X=4}whenn=9,p=.2.

An interviewer is given a list of people she can interview. If the interviewer needs to interview 5 people, and if each person (independently) agrees to be interviewed with probability 2 3 , what is the probability that her list of people will enable her to obtain her necessary number of interviews if the list consists of

(a) 5 people and

(b) 8 people? For part (b), what is the probability that the interviewer will speak to exactly

(c) 6 people and

(d) 7 people on the list?

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