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A population is made up of r disjoint subgroups. Let pi denote the proportion of the population that is in subgroup i,i=1,,r. If the average weight of the members of subgroup i is wi,i=1,,r, what is the average weight of the members of the population?

Short Answer

Expert verified

The average weight of the members of the population isE(W)=Wipi

Step by step solution

01

Given information

Given in the question that, A population is made up of rdisjoint subgroups. Let pidenote the proportion of the population that is in subgroup i,i=1,,r. If the average weight of the members of subgroup is wi,i=1,...,r,

02

Explanation

Allow Wto mean the pay of an arbitrary part. We are given that

EWAi=wi

where Aiis the occasion that an irregular part comes from subgroup i. Utilizing the law of the total expectation, we have that

E(W)=iEWAiPAi=iwipi

03

Final answer

The average weight of the members of the population isE(W)=wipi

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Most popular questions from this chapter

Two envelopes, each containing a check, are placed in front of you. You are to choose one of the envelopes, open it, and see the amount of the check. At this point, either you can accept that amount or you can exchange it for the check in the unopened envelope. What should you do? Is it possible to devise a strategy that does better than just accepting the first envelope? Let Aand B, A<B, denote the (unknown) amounts of the checks and note that the strategy that randomly selects an envelope and always accepts its check has an expected return of (A+B)/2. Consider the following strategy: Let F(·)be any strictly increasing (that is, continuous) distribution function. Choose an envelope randomly and open it. If the discovered check has the value x, then accept it with probability F(x)and exchange it with probability 1F(x).

(a) Show that if you employ the latter strategy, then your expected return is greater than (A+B)/2. Hint: Condition on whether the first envelope has the value Aor B. Now consider the strategy that fixes a value x and then accepts the first check if its value is greater than x and exchanges it otherwise. (b) Show that for any x, the expected return under thex-strategy is always at least (A+B)/2and that it is strictly larger than (A+B)/2if xlies between Aand B.

(c) Let X be a continuous random variable on the whole line, and consider the following strategy: Generate the value ofX, and if X=x, then employ the x-strategy of part (b). Show that the expected return under this strategy is greater than (A+B)/2.

Let X1,...be independent with common mean μand common variance σ2, and set Yn=Xn+Xn+1+Xn+2. For j0, find CovYn,Yn+j.

Consider the following dice game, as played at a certain gambling casino: Players1and 2roll a pair of dice in turn. The bank then rolls the dice to determine the outcome according to the following rule: Playeri,i=1,2,wins if his roll is strictly greater than the banks. Fori=1,2,let

Ii=1    ifiwins0    otherwise

and show that I1and I2are positively correlated. Explain why this result was to be expected.

The joint density of X and Y is given by

f(x,y)=12πe-ye-(x-y)2/20<y<,

-<x<

(a) Compute the joint moment generating function of X and Y.

(b) Compute the individual moment generating functions.

We say that Xis stochastically larger than Y, written XstY, if, for all t,

P{X>t}P{Y>t}

Show that if XstYthen E[X]E[Y]when

(a) Xand Yare nonnegative random variables;

(b) Xand Yare arbitrary random variables. Hint:

Write Xas

X=X+-X-

where

X+=X    ifX00    ifX<0,X=0ifX0XifX<0

Similarly, represent Y as Y+-Y-. Then make use of part (a).

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