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Prove directly that,

P(EF)=P(EFG)P(GF)+PEFGcPGcF.

Short Answer

Expert verified

By applying the definition of conditional probability,the direction starting from the right side.

Step by step solution

01

Step: 1 Conditional probability:

The potential of an event or outcome occurring dependent on the existence of a preceding event or outcome is known as conditional probability. It's computed by multiplying the likelihood of the previous occurrence by the probability of the next, or conditional, event.

02

Step: 2 Proving equation:

By conditional probability,

P(EFG)P(GF)+PEFGcPGcF=P(EFG)P(GF)×P(GF)P(F)+PEFGcPGcF×PGcFP(F)P(EFG)P(GF)+PEFGcPGcF=P(EFG)P(F)+PEFGcP(F)P(EFG)P(GF)+PEFGcPGcF=P(EF)P(F)P(EFG)P(GF)+PEFGcPGcF=P(EF).

03

Step: 3 Equating probability:

In total probability,

PF=P(F)PF(EG)=PF(EG)PF(G)PF(EG)=P(EG[F)P(GF)PF(EG)=P(EFG)P(F)P(FG)P(F)PF(EG)=P(EFG).

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