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How many different letter arrangements can be made from the letters (a) Fluke? (b) Propose? (c) Mississippi? (d) Arrange?

Short Answer

Expert verified

Part(a) .different letter arrangements for Fluke is 120

Part(b). different letter arrangements for Propose is 1260

Part(c), different letter arrangements for Mississippi is 34650

Part(d) . different letter arrangements for Arrange is 1260

Step by step solution

01

Step 1. Part( a) Given information

We have to find the different letter arrangements for Fluke

02

, Part(a). Different letter arrangements for Fluke 

In the word Fluke there are 5 different letters, then the different letter arrangement for ' the word Fluke is5!=5ร—4ร—3ร—2ร—1=120

03

Step 1.Part(b) . Given information 

we have to find different letter arrangements for Propose

04

Step 2.Part(b) . different letter arrangements  for Propose 

here are 7 seven letters in the word Propose, out of letters 2 identical letters of p and o. So to get different letter arrangements for the given word we have to divide 7! by identical word arrangements 2! and 2!. Then the different letter arrangements for the word Propose is

7!2!2!=7ร—6ร—5ร—4ร—3ร—2ร—12ร—1ร—2ร—'1=1260

05

Step 1.Part(c),Given  information

Here we have to find different letter arrangements for Mississippi

06

Step 2.Part(c).different letter arrangements  for Mississippi 

In the word Mississippi, there are a total of 11 letters out of 11, there are d identical i letter, 4 identical s letters, and 2 identical letters p. Then to get a different word arrangement we have to divide 11! by each identical letter arrangement, thus the different letter arrangements for the word is

11!4!ร—4!ร—2!=11ร—10ร—9ร—8ร—7ร—6ร—5ร—4!4ร—3ร—2ร—1ร—4!ร—2ร—1=34650

07

,Part(d). Given information

we need to find different letter arrangements for Arrange

08

Part (d). different letter arrangements  for Arrange 

in this word Arrange there are a total of 7letters, in which 2 identical letters a and 2 identical letters r are there. To get different letter arrangements we have to divide 7! by identical arrangements, then the arrangements will be

7!2!ร—2!=7ร—6ร—5ร—4ร—3ร—2!1ร—2ร—2!=1260

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Most popular questions from this chapter

Delegates from 10countries, including Russia, France, England, and the United States, are to be seated in a row. How many different seating arrangements are possible if the French and English delegates are to be seated next to each other and the Russian and U.S. delegates are not to be next to each other?

Consider a tournament of ncontestants in which the outcome is an ordering of these contestants, with ties allowed. That is, the outcome partitions the players into groups, with the first group consisting of the players who tied for first place, the next group being those who tied for the next-best position, and so on. Let localid="1648231792067" N(n)denote the number of different possible outcomes. For instance, localid="1648231796484" N(2)=3, since, in a tournament with localid="1648231802600" 2contestants, player localid="1648231807229" 1could be uniquely first, player localid="1648231812796" 2could be uniquely first, or they could tie for first.

(a) List all the possible outcomes when n=3.

(b) With localid="1648231819245" N(0)defined to equal localid="1648231826690" 1, argue without any computations, that localid="1648281124813" N(n)=โˆ‘i=1nniNn-i

Hint: How many outcomes are there in which localid="1648231837145" iplayers tie for last place?

(c) Show that the formula of part (b) is equivalent to the following:

localid="1648285265701" N(n)=โˆ‘i=1n-1niNi

(d) Use the recursion to find N(3) and N(4).

Determine the number of vectors (x1,...,xn)such that each xiis a positive integer and

role="math" localid="1649161391681" โˆ‘i=1nxiโ‰คk

wherekโ‰ฅn.

If 8identical blackboards are to be divided among 4schools, how many divisions are possible? How many of each school must receive at least 1a blackboard?

In a certain community, there are 3 families consisting of a single parent and 1 child, 3 families consisting of a single parent and 2 children, 5 families consisting of 2 parents and a single child, 7 families consisting of 2 parents and 2 children, and 6 families consisting of 2 parents and 3 children. If a parent and child from the same family are to be chosen, how many possible choices are there?

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