Question

Suppose that a person chooses a letter at random from R E S E R V E and then chooses one at random from V E R T I C A L. What is the probability that the same letter is chosen?

Short answer

Probability of choosing letter which exist in both would be P(A intersection B)$=$P(A)$·$P(B)$=\frac{1}{56}$

Step-by-step solution

Step 1. Finding probability of RESERVE

Probability of choosing letter from "RESERVE" is P(B)$=\frac{1}{7}$

Step 2. Finding probability of VERTICAL 

Probability of choosing letter from "VERTICAL" is P(B)$=\frac{1}{8}$

Step 3. Finding probability of choosing a letter which exist in both

Probability of choosing a letter which exist in both would be P(A intersection B)$=$P(A).P(B)$=\frac{1}{56}$