Chapter 9: Problem 3
This exercise is concerned with proofs. Let \(\mathbf{f}(\mathbf{x})\) be Lipschitz continuously differentiable in an open convex set \(\mathcal{D} \subset \mathcal{R}^{n}\), i.e., there is a constant \(\gamma \geq 0\) such that $$ \|J(\mathbf{x})-J(\mathbf{y})\| \leq \gamma\|\mathbf{x}-\mathbf{y}\| \quad \forall \mathbf{x}, \mathbf{y} \in \mathcal{D} $$ where \(J\) is the \(n \times n\) Jacobian matrix of \(\mathbf{f}\). It is possible to show that if \(\mathbf{x}\) and \(\mathbf{x}+\mathbf{p}\) are in \(\mathcal{D}\), then $$ \mathbf{f}(\mathbf{x}+\mathbf{p})=\mathbf{f}(\mathbf{x})+\int_{0}^{1} J(\mathbf{x}+\tau \mathbf{p}) \mathbf{p} d \tau $$ (a) Assuming the above as given, show that $$ \|\mathbf{f}(\mathbf{x}+\mathbf{p})-\mathbf{f}(\mathbf{x})-J(\mathbf{x}) \mathbf{p}\| \leq \frac{\gamma}{2}\|\mathbf{p}\|^{2} $$ (b) Suppose further that there is a root \(\mathbf{x}^{*} \in \mathcal{D}\) satisfying $$ \mathbf{f}\left(\mathbf{x}^{*}\right)=\mathbf{0}, \quad J\left(\mathbf{x}^{*}\right) \text { nonsingular. } $$ Show that for \(\mathbf{x}_{0}\) sufficiently close to \(\mathbf{x}^{*}\), Newton's method converges quadratically.
Short Answer
Step by step solution
Key Concepts
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