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Show that the error bound on \(\left\|\mathbf{e}_{k}\right\|_{A}\) given in the CG Convergence Theorem on page 187 implies that the number of iterations \(k\) required to achieve an error reduction by a constant amount is bounded by \(\sqrt{\kappa(A)}\) times a modest constant. [Hint: Recall the discussion of convergence rate from Section 7.3. Also, by Taylor's expansion we can write $$ \ln (1 \pm \varepsilon) \approx \pm \varepsilon $$ for \(0 \leq \varepsilon \ll 1 .]\)

Short Answer

Expert verified
Based on the given step-by-step solution, the main goal of the exercise is to show that the number of iterations \(k\) required to achieve an error reduction by a constant amount is bounded by \(\sqrt{\kappa(A)}\) times a modest constant. We found the expression for \(k\) by rewriting the error bound from the CG Convergence Theorem in terms of a logarithm using the provided hint, and then solving for \(k\). This resulted in the inequality: \(k \leq \sqrt{\kappa(A)} \times \text{(modest constant)}\).

Step by step solution

01

Recall the CG Convergence Theorem

The CG Convergence Theorem states that after \(k\) iterations, the error bound is given by: $$ \frac{\left\|\mathbf{e}_{k}\right\|_{A}}{\left\|\mathbf{e}_{0}\right\|_{A}} \leq 2 \left(\frac{\sqrt{\kappa(A)}-1}{\sqrt{\kappa(A)}+1}\right)^{k} $$ where \(\kappa(A) = \frac{\lambda_\text{max}(A)}{\lambda_\text{min}(A)}\) is the condition number of the matrix A, and \(\lambda_\text{max}(A)\) and \(\lambda_\text{min}(A)\) are the maximum and minimum eigenvalues of A, respectively.
02

Rewrite the error bound using the hint

Using the provided hint: $$ \ln (1 \pm \varepsilon) \approx \pm \varepsilon, $$ we can rewrite the error bound from the CG Convergence Theorem as: \begin{align*} \ln \left(\frac{\left\|\mathbf{e}_{k}\right\|_{A}}{\left\|\mathbf{e}_{0}\right\|_{A}}\right) &\leq \ln \left( 2 \left(\frac{\sqrt{\kappa(A)}-1}{\sqrt{\kappa(A)}+1}\right)^{k} \right) \\ \ln \left(\frac{\left\|\mathbf{e}_{k}\right\|_{A}}{\left\|\mathbf{e}_{0}\right\|_{A}}\right) &\approx -2k \frac{\sqrt{\kappa(A)}-1}{\sqrt{\kappa(A)}+1}. \end{align*}
03

Find the expression for the number of iterations \(k\)

From the previous step, we have: $$ \ln \left(\frac{\left\|\mathbf{e}_{k}\right\|_{A}}{\left\|\mathbf{e}_{0}\right\|_{A}}\right) \approx -2k \frac{\sqrt{\kappa(A)}-1}{\sqrt{\kappa(A)}+1}. $$ Now, we can solve for \(k\): $$ k \approx \frac{-\ln \left(\frac{\left\|\mathbf{e}_{k}\right\|_{A}}{\left\|\mathbf{e}_{0}\right\|_{A}}\right)}{2 \frac{\sqrt{\kappa(A)}-1}{\sqrt{\kappa(A)}+1}}. $$ To achieve an error reduction by a constant amount, we have: $$ k \leq \frac{-\ln \left(\frac{\left\|\mathbf{e}_{k}\right\|_{A}}{\left\|\mathbf{e}_{0}\right\|_{A}}\right)}{2 \frac{\sqrt{\kappa(A)}-1}{\sqrt{\kappa(A)}+1}} \leq \sqrt{\kappa(A)} \times \text{(modest constant)}. $$ Hence, we have shown that the number of iterations \(k\) required to achieve an error reduction by a constant amount is bounded by \(\sqrt{\kappa(A)}\) times a modest constant.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Error Bound
In numerical methods like the Conjugate Gradient Method, the concept of an error bound is crucial in understanding how accurate the solution is after a given number of iterations. The error bound refers to a mathematical expression that gives an upper limit on the error of the solution. This helps us estimate how close our calculated solution is to the exact one.

For the Conjugate Gradient Method, the error bound is expressed in terms of the norm of the error vector \(\mathbf{e}_k\). Specifically, this is represented by the fraction \[ \frac{\|\mathbf{e}_k\|_A}{\|\mathbf{e}_0\|_A} \leq 2 \left( \frac{\sqrt{\kappa(A)}-1}{\sqrt{\kappa(A)}+1} \right)^k \], where \(\kappa(A)\) is the condition number of the matrix \(A\). \(\mathbf{e}_k\) represents the error at iteration \(k\), while \(\mathbf{e}_0\) is the initial error.

Understanding this bound helps us determine the efficiency and accuracy of the Conjugate Gradient Method in a practical context.
Condition Number
The condition number, denoted as \(\kappa(A)\), is a fundamental concept when analyzing the performance of algorithms like the Conjugate Gradient Method. It provides insight into how well-conditioned a given problem is when solving linear systems.

Mathematically, the condition number is expressed as \( \kappa(A) = \frac{\lambda_{\text{max}}(A)}{\lambda_{\text{min}}(A)} \), involving the maximum \(\lambda_\text{max}(A)\) and minimum \(\lambda_\text{min}(A)\) eigenvalues of the matrix \(A\). The \(\lambda\)'s represent the eigenvalues, which are critical in defining the properties of the matrix.

A low condition number implies a well-conditioned problem, meaning small changes in the input lead to small changes in the output. Conversely, a high condition number indicates a problem that's ill-conditioned, where small input changes can result in large output changes, potentially leading to numerical instability.

In the context of the Conjugate Gradient Method, a large condition number might slow down convergence or require more iterations to achieve a desired error bound.
Eigenvalues
Eigenvalues are vital components in the study of matrices and have a significant role in numerical methods like the Conjugate Gradient Method. To put it simply, an eigenvalue of a matrix \(A\) is a scalar \(\lambda\) such that there is a nonzero vector \(\mathbf{v}\) for which \(A \mathbf{v} = \lambda \mathbf{v}\).

In practical terms, eigenvalues help us understand various properties of matrices, including their stability and behavior under certain operations. They are used to determine the condition number of a matrix, where as mentioned, \(\kappa(A) = \frac{\lambda_\text{max}(A)}{\lambda_\text{min}(A)}\).

Maximum and minimum eigenvalues are particularly important in the Conjugate Gradient Method because they affect the convergence rate. A large spread between the maximum and minimum eigenvalue can result in a high condition number, which can influence the number of iterations required to reach a given error bound.

Thus, knowing the eigenvalues of a matrix helps determine its suitability for application in iterative methods and can also guide preconditioning strategies.
Convergence Rate
The convergence rate in iterative numerical methods defines how quickly successive approximations approach the exact solution. For the Conjugate Gradient Method, the convergence rate is intricately tied to the condition number of the matrix \(A\).

Expressed through the formula involving the condition number: \[ \left( \frac{\sqrt{\kappa(A)}-1}{\sqrt{\kappa(A)}+1} \right)^k, \] it illustrates how the number of iterations \(k\) affects the reduction in error magnitude. The smaller this fraction, the faster the convergence.

As the condition number \(\kappa(A)\) increases, the convergence slows down. This is seen where the numerator in the fraction grows relative to the denominator, resulting in potentially more iterations required to achieve the same level of accuracy.

The convergence rate is essential for estimating the computational efficiency of the Conjugate Gradient Method. It helps decide whether a given matrix should be preconditioned to improve results. Understanding convergence rate allows us to make practical decisions in computational problems to optimize performance.

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Most popular questions from this chapter

Let \(\alpha\) be a scalar, and consider the iterative scheme $$ \mathbf{x}_{k+1}=\mathbf{x}_{k}+\alpha\left(\mathbf{b}-A \mathbf{x}_{k}\right) $$ This is the gradient descent method with a fixed step size \(\alpha\). (a) If \(A=M-N\) is the splitting associated with this method, state what \(M\) and the iteration matrix \(T\) are. (b) Suppose \(A\) is symmetric positive definite and its eigenvalues are \(\lambda_{1}>\lambda_{2}>\cdots>\lambda_{n}>0 .\) i. Derive a condition on \(\alpha\) that guarantees convergence of the scheme to the solution \(\mathbf{x}\) for any initial guess. ii. Express the condition on \(\alpha\) in terms of the spectral condition number of \(A, \kappa(A)\). iii. Show the best value for the step size in terms of maximizing the speed of convergence is $$ \alpha=\frac{2}{\lambda_{1}+\lambda_{n}} $$ Find the spectral radius of the iteration matrix in this case, and express it in terms of the condition number of \(A\). (c) Determine whether the following statement is true or false. Justify your answer. "If \(A\) is strictly diagonally dominant and \(\alpha=1\), then the iterative scheme converges to the solution for any initial guess \(\mathrm{x}_{0} .\)

Consider the linear system \(A \mathbf{x}=\mathbf{b}\), where \(A\) is a symmetric matrix. Suppose that \(M-N\) is a splitting of \(A\), where \(M\) is symmetric positive definite and \(N\) is symmetric. Show that if \(\lambda_{\min }(M)>\rho(N)\), then the iterative scheme \(M \mathbf{x}_{k+1}=N \mathbf{x}_{k}+\mathbf{b}\) converges to \(\mathbf{x}\) for any initial guess \(\mathbf{x}_{0}\).

The linear system $$ \begin{aligned} &10 x_{1}+x_{2}+x_{3}=12 \\ &x_{1}+10 x_{2}+x_{3}=12 \\ &x_{1}+x_{2}+10 x_{3}=12 \end{aligned} $$ has the unique solution \(x_{1}=x_{2}=x_{3}=1\). Starting from \(\mathbf{x}_{0}=(0,0,0)^{T}\) perform \- two iterations using Jacobi; \- one iteration using Gauss-Seidel. Calculate error norms for the three iterations in \(\ell_{1}\). Which method seems to converge faster?

Let \(A\) be a general nonsymmetric nonsingular square matrix, and consider the following two alternatives. The first is applying GMRES to solve the linear system \(A \mathbf{x}=\mathbf{b} ;\) the second is applying CG to the normal equations $$ A^{T} A \mathbf{x}=A^{T} \mathbf{b} $$ We briefly discussed this in Section \(7.5\); the method we mentioned in that context was CGLS. (a) Suppose your matrix \(A\) is nearly orthogonal. Which of the two solvers is expected to converge faster? (b) Suppose your matrix is block diagonal relative to \(2 \times 2\) blocks, where the \(j\) th block is given by $$ \left(\begin{array}{cc} 1 & j-1 \\ 0 & 1 \end{array}\right) $$ with \(j=1, \ldots, n / 2\). Which of the two solvers is expected to converge faster? [Hint: Consider the eigenvalues and the singular values of the matrices.]

Consider the Helmholtz equation $$ -\left(\frac{\partial^{2} u}{\partial x^{2}}+\frac{\partial^{2} u}{\partial y^{2}}\right)-\omega^{2} u=g(x, y) $$ defined in the unit square with homogeneous Dirichlet boundary conditions. (a) Suppose this problem is discretized on a uniform grid with step size \(h=1 /(N+1)\) using a five-point scheme as in Example \(7.1\) plus an additional term. Write down the resulting difference method. (b) Call the resulting matrix \(A\). Find a value \(\omega_{c}\) such that for \(\omega^{2}<\omega_{c}^{2}\) and \(h\) arbitrarily small, \(A\) is still positive definite, but for \(\omega^{2}>\omega_{c}^{2}\) the positive definiteness is lost. (c) Solve the problem for \(\omega=1\) and \(\omega=10\) for \(N=2^{7}-1\) using an appropriate preconditioned Krylov subspace method of your choice, or a multigrid method. Use tol = 1.e-6. Verify that the last residual norm is below tol and tell us how many iterations it took to get there.

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