Chapter 7: Problem 15
Show that the energy norm is indeed a norm when the associated matrix is symmetric positive definite.
Short Answer
Expert verified
Answer: Yes, the energy norm is a norm when the associated matrix is symmetric positive definite. This is proven by demonstrating that the energy norm satisfies the three properties of a norm, including the positivity, linearity, and the triangle inequality.
Step by step solution
01
Definition of Energy Norm and Symmetric Positive Definite Matrix
First, let's recall the definition of the energy norm associated with a symmetric positive definite matrix A.
An energy norm is defined as:
\[ ||x||_A = \sqrt{(x^T A x)} \]
A matrix A is symmetric positive definite if it satisfies:
1. A = A^T (symmetric)
2. x^T A x > 0 for all non-zero vectors x (positive definite)
02
Property 1: Proving Positivity
We need to show that the energy norm is always non-negative and is equal to zero if and only if x is the zero vector.
Since A is symmetric positive definite,
\[ x^T A x > 0 \] for all non-zero vectors x.
Therefore,
\[ ||x||_A = \sqrt{(x^T A x)} \ge 0 \]
If x is the zero vector,
\[ ||x||_A = \sqrt{(0^T A 0)} = 0 \]
If ||x||_A = 0, it is clear that x=0, since \[x^T A x = 0 \] only if x is the zero vector.
Hence, the energy norm satisfies the positivity property of a norm.
03
Property 2: Proving Linearity
We need to show that for any scalar α and any vector x, ||αx||_A = |α| * ||x||_A.
\[ ||\alpha x||_A = \sqrt{((\alpha x)^T A (\alpha x))} = \sqrt{(\alpha^2 x^T A x)} = |\alpha| \sqrt{(x^T A x)} = |\alpha| ||x||_A \]
Thus, the energy norm satisfies the linearity property of a norm.
04
Property 3: Proving Triangle Inequality
We need to show that for any two vectors x and y, ||x + y||_A ≤ ||x||_A + ||y||_A.
This can be shown by applying the Cauchy-Schwarz inequality which states that for any vectors x and y,
\[ (x^T y)^2 \le (x^T x)(y^T y) \]
Applying the inequality, we get
\[ ||x + y||_A^2 = (x + y)^T A (x + y) = x^T A x + 2x^T A y + y^T A y \le x^T A x + 2 |x^T A y| + y^T A y \]
Using Cauchy-Schwarz inequality with A^{1/2}x and A^{1/2}y, we have
\[ (x^T A y)^2 \le (x^T A x)(y^T A y) \]
Now, we need to show that
\[ \sqrt{x^T A x + 2 |x^T A y| + y^T A y} \le \sqrt{x^T A x} + \sqrt{y^T A y} \]
Square both sides of the inequality:
\[ x^T A x + 2 |x^T A y| + y^T A y \le x^T A x + 2 \sqrt{(x^T A x)(y^T A y)} + y^T A y \]
This inequality holds based on our application of the Cauchy-Schwarz inequality on the left side terms. Hence,
\[ ||x + y||_A \le ||x||_A + ||y||_A \]
So, the energy norm satisfies the triangle inequality property of a norm.
By showing that the energy norm satisfies the properties of positivity, linearity, and the triangle inequality, we have demonstrated that the energy norm is indeed a norm when the associated matrix is symmetric positive definite.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
symmetric positive definite matrix
A symmetric positive definite matrix, often abbreviated as SPD matrix, is an essential concept in linear algebra that is widely used in calculus and numerical computations. To fully understand this concept, it's important to break down its properties:
- Symmetry: A matrix \( A \) is symmetric if it is equal to its transpose, which means \( A = A^T \). This property ensures that the matrix behaves uniformly in all directions.
- Positive Definiteness: A matrix \( A \) is positive definite if \( x^T A x > 0 \) for all non-zero vectors \( x \). This property guarantees that the quadratic form \( x^T A x \) always yields a positive value, except when the vector is the zero vector.
Cauchy-Schwarz inequality
The Cauchy-Schwarz inequality is a cornerstone in the study of vector spaces, providing a fundamental property that relates to the inner product of vectors. It's expressed as follows:
In the context of norms, the Cauchy-Schwarz inequality helps in proving the triangle inequality property. By guaranteeing an upper bound on the product \( |x^T A y| \), we can assert control over combined vector magnitudes, a critical step when proving certain properties of the energy norm.
- For any two vectors \( x \) and \( y \) in an inner product space, \( (x^T y)^2 \le (x^T x)(y^T y) \).
In the context of norms, the Cauchy-Schwarz inequality helps in proving the triangle inequality property. By guaranteeing an upper bound on the product \( |x^T A y| \), we can assert control over combined vector magnitudes, a critical step when proving certain properties of the energy norm.
triangle inequality
The triangle inequality is an easily remembered concept derived from the physical properties of triangles in geometry. In the context of norms, it provides a meaningful way to understand distances in vector spaces. Specifically, for any vectors \( x \) and \( y \), the triangle inequality states:
In proving this property for the energy norm, combining the positive definiteness of the matrix with the Cauchy-Schwarz inequality plays a key role. This ensures that no unexpected behavior appeared when adding vectors, such as longer-than-expected vector lengths, thus maintaining the robustness of the norm structure.
- \( ||x + y||_A \le ||x||_A + ||y||_A \)
In proving this property for the energy norm, combining the positive definiteness of the matrix with the Cauchy-Schwarz inequality plays a key role. This ensures that no unexpected behavior appeared when adding vectors, such as longer-than-expected vector lengths, thus maintaining the robustness of the norm structure.
norm properties
Norms are a fundamental concept in the study of vector spaces, quantifying the "size" or "length" of vectors. A well-defined norm must satisfy the following three properties:
- Non-negativity: For any vector \( x \), \( ||x|| \ge 0 \), and \( ||x|| = 0 \) if and only if \( x \) is the zero vector.
- Scalability: For any scalar \( \alpha \) and vector \( x \), \( ||\alpha x|| = |\alpha| ||x|| \). This property ensures that scaling a vector increases or decreases its norm proportionally.
- Triangle Inequality: For any vectors \( x \) and \( y \), the sum of their norms satisfies \( ||x + y|| \le ||x|| + ||y|| \).