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Let \(A\) be a symmetric positive definite \(n \times n\) matrix with entries \(a_{i j}\) that are nonzero only if one of the following holds: \(i=1\), or \(i=n\), or \(j=1\), or \(j=n\), or \(i=j\). Otherwise, \(a_{i j}=0\). (a) Show that only \(5 n-6\) of the \(n^{2}\) elements of \(A\) are possibly nonzero. (b) Plot the zero-structure of \(A\). (In MATLAB you can invent such a matrix for \(n=20\), say, and use spy (A).) (c) Explain why for \(n=100,000\) using chol (see Section 5.5) to solve \(A \mathbf{x}=\mathbf{b}\) for a given right-hand-side vector would be problematic.

Short Answer

Expert verified
#Short Answer# For the given n×n symmetric positive definite matrix A, there are (5n - 6) possible nonzero elements. The zero-structure of A resembles a square frame with an additional diagonal line passing through. When solving Ax=b using Cholesky factorization for a large value of n, the computational complexity and memory requirements may become inefficient and problematic due to the sparsity of the matrix A, and alternative methods such as sparse matrix factorizations are often preferred.

Step by step solution

01

Count the nonzero elements

According to the given conditions, the elements of A will be nonzero in the following cases: * i = 1: There are n elements in the first row. * i = n: There are n elements in the last row. * j = 1: There are n elements in the first column. * j = n: There are n elements in the last column. * i = j: There are n elements on the main diagonal. Since the matrix A is symmetric, the elements in the first and last rows and columns are already accounted for, and we are left with only the elements on the main diagonal. Therefore, there are 4n + (n-2) nonzero elements. Simplifying this expression gives: $$ 5n - 6 $$
02

Plot the zero-structure of A

The elements on the first row, the last row, the first column, the last column, and the main diagonal will be nonzero. The pattern will look like a square frame with an additional diagonal line passing through. This can be visualized as follows: - - - - - - - - - × × × × × × - - × - - - - × - - × - - - - × - - × - - - - × - - - × × × × × - Here, the dashes represent zero elements and the "×" symbols represent nonzero elements.
03

Issues with solving Ax=b for large n using Cholesky factorization

For a large value of n, such as n=100,000, the number of nonzero elements in A is still very sparse (i.e., around 500,000 nonzero elements out of 10,000,000,000 total elements). However, the Cholesky factorization requires the computation of the complete lower triangular matrix, which increases the computational complexity and memory requirements significantly. This can make solving Ax=b for large n using Cholesky factorization inefficient and problematic, especially when dealing with sparse matrices like A. Instead, more efficient methods such as sparse matrix factorizations are often preferred for solving large sparse systems Ax=b.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cholesky factorization
Cholesky factorization is a method used to decompose a symmetric positive definite matrix into a product of a lower triangular matrix and its conjugate transpose. This technique can be represented as
\[ A = LL^T \]
where \( A \) is the original matrix, \( L \) is the lower triangular matrix, and \( L^T \) is the transpose of \( L \). This decomposition is especially useful for solving systems of linear equations
\[ A\mathbf{x} = \mathbf{b} \]
as it allows for efficient forward and backward substitution without the need for traditional Gaussian elimination methods.For instance, Cholesky factorization can be a faster alternative when dealing with dense systems, as it takes advantage of the inherent symmetry in the matrix structure. However, when the matrix is sparse, or when \( n \) becomes very large, as in the given exercise where \( n = 100,000 \), this efficiency can be overshadowed by the sheer scale of the calculations and storage requirements, rendering the method less effective for practical large-scale computing.
Sparse matrix
A sparse matrix is one in which most of the elements are zero. In computational mathematics and applications that involve large datasets, the representation and processing of sparse matrices are critical for efficiency in both time and space. Efficient storage schemes, such as the Compressed Sparse Row (CSR) or Compressed Sparse Column (CSC) formats, store only the nonzero elements and their respective indices, significantly reducing memory usage.
In the exercise, the given conditions imply a specific sparsity pattern where only boundary-related elements and the diagonal elements are nonzero. This means that the vast majority of the matrix is composed of zeros, ideal for sparse matrix techniques.
While the Cholesky factorization is useful, it might lead to a 'fill-in' phenomenon where zeros in the original sparse matrix \( A \) become nonzero in the factor \( L \), thereby negating the benefits of sparsity. In large-scale problems, algorithms designed for sparse matrix computations, like the conjugate gradient method for positive definite matrices, often offer improved performance over Cholesky factorization by capitalizing on the sparsity to minimize computation and storage.
Numerical methods
Numerical methods are algorithms used for approximating solutions to mathematical problems that cannot be solved analytically. These methods are designed to handle the challenges posed by complex real-world problems, often involving large-scale computations or data sets.
When faced with large, sparse systems of equations like the one described in the exercise, numerical methods can provide efficient solutions without necessitating the complete evaluation of all matrix elements. Iterative methods, for example, can exploit the sparse structure to gradually approximate the solution, often requiring less memory and computational power than direct methods such as Cholesky factorization.
The design of these algorithms focuses on reducing computational complexity and optimizing memory usage. Using numerical algorithms that directly tackle sparsity can thus significantly decrease the resource demand, enabling the solution of large systems that would otherwise be computationally infeasible due to resource limitations. For students working with sparse matrices or very large datasets, understanding the principles behind these numerical methods is crucial for selecting the most appropriate algorithm to solve their problem.

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Most popular questions from this chapter

The damped Jacobi (or under-relaxed Jacobi) method is briefly described in Sections \(7.2\) and \(7.6\). Consider the system \(A \mathbf{x}=\mathbf{b}\), and let \(D\) be the diagonal part of \(A\). (a) Write down the corresponding splitting in terms of \(D, A\), and \(\omega\). (b) Suppose \(A\) is again the same block tridiagonal matrix arising from discretization of the two-dimensional Poisson equation. i. Find the eigenvalues of the iteration matrix of the damped Jacobi scheme. ii. Find the values of \(\omega>0\) for which the scheme converges. iii. Determine whether there are values \(\omega \neq 1\) for which the performance is better than the performance of standard Jacobi, i.e., with \(\omega=1\).

Show that the energy norm is indeed a norm when the associated matrix is symmetric positive definite.

Define a linear problem with \(n=500\) using the script \(A=\operatorname{randn}(500,500) ; x t=\operatorname{randn}(500,1) ; b=A * x t\) Now we save xt away and solve \(A \mathbf{x}=\mathbf{b} .\) Set tol \(=1 . \mathrm{e}-6\) and maximum iteration limit of 2000\. Run three solvers for this problem: (a) \(\mathrm{CG}\) on the normal equations: \(A^{T} A \mathbf{x}=A^{T} \mathbf{b}\). (b) GMRES(500). (c) GMRES(100), i.e., restarted GMRES with \(m=100\). Record residual norm and solution error norm for each run. What are your conclusions?

Write a program that solves the problem of Example \(7.13\) for \(N=127\) and \(N=255\) using a multigrid method. The script in that example and the code for a V-cycle in Section \(7.6\) should prove useful with appropriate modification. Set your coarsest level (where the problem is solved exactly, say, by a direct solver) to \(N=31\). You should be able to obtain considerably faster convergence than in Example \(7.13\) at the price of a considerable headache.

Let \(\alpha\) be a scalar, and consider the iterative scheme $$ \mathbf{x}_{k+1}=\mathbf{x}_{k}+\alpha\left(\mathbf{b}-A \mathbf{x}_{k}\right) $$ This is the gradient descent method with a fixed step size \(\alpha\). (a) If \(A=M-N\) is the splitting associated with this method, state what \(M\) and the iteration matrix \(T\) are. (b) Suppose \(A\) is symmetric positive definite and its eigenvalues are \(\lambda_{1}>\lambda_{2}>\cdots>\lambda_{n}>0 .\) i. Derive a condition on \(\alpha\) that guarantees convergence of the scheme to the solution \(\mathbf{x}\) for any initial guess. ii. Express the condition on \(\alpha\) in terms of the spectral condition number of \(A, \kappa(A)\). iii. Show the best value for the step size in terms of maximizing the speed of convergence is $$ \alpha=\frac{2}{\lambda_{1}+\lambda_{n}} $$ Find the spectral radius of the iteration matrix in this case, and express it in terms of the condition number of \(A\). (c) Determine whether the following statement is true or false. Justify your answer. "If \(A\) is strictly diagonally dominant and \(\alpha=1\), then the iterative scheme converges to the solution for any initial guess \(\mathrm{x}_{0} .\)

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