Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Suggest a way to determine approximately the rounding unit of your calculator. State the type of calculator you have and the rounding unit you have come up with. If you do not have a calculator, write a short MATLAB script to show that your algorithm works well on the standard IEEE floating point system.

Short Answer

Expert verified
Answer: To determine the rounding unit, we can use a method where we add successive smaller numbers to a larger number and observe when the result changes. This change indicates the rounding unit. We can perform this experiment in MATLAB by writing a script that initializes variables, uses a while loop to keep updating the smaller number until the result changes, and then displays the rounding unit.

Step by step solution

01

Choose a Calculator or MATLAB

In this case, let's write a short MATLAB script to determine the rounding unit on the standard IEEE floating point system.
02

Initialize Variables

We will choose a larger number and a smaller number to begin with. We will keep decreasing the smaller number until we find the rounding unit. ```MATLAB large_number = 1; small_number = 1; result = large_number + small_number; ```
03

Determine the Rounding Unit

Use a while loop to keep updating the smaller number by dividing it by 2 until the result changes. When the result changes, we know we are at the rounding unit. ```MATLAB previous_result = result; while result == previous_result small_number = small_number / 2; result = large_number + small_number; end ```
04

Display the Rounding Unit

When the while loop ends, we have found the rounding unit. Display the result by printing the value of the smaller number. ```MATLAB fprintf('The rounding unit is approximately: %.16f\n', small_number); ```
05

Complete MATLAB Script

Here is the complete MATLAB script that determines the rounding unit for the standard IEEE floating point system. ```MATLAB % Initialize variables large_number = 1; small_number = 1; result = large_number + small_number; % Determine the rounding unit previous_result = result; while result == previous_result small_number = small_number / 2; result = large_number + small_number; end % Display the rounding unit fprintf('The rounding unit is approximately: %.16f\n', small_number); ``` By running this script in MATLAB, we can find the rounding unit of the standard IEEE floating point system.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

IEEE Floating Point System
The IEEE floating point system is a widely adopted standard for representing and computing with real numbers in computers. It helps maintain consistency and accuracy across different computing platforms. At its core, the IEEE floating point system utilizes binary to encode real numbers, enabling precise and consistent computations.
This encoding involves two key components: the mantissa (or significant) and the exponent, formatted in a special way to allow the representation of both extremely large and extremely small numbers.
When performing arithmetic operations, tiny discrepancies known as rounding errors can occur due to the finite precision of these numbers. The rounding unit is a critical concept here, and it essentially describes the smallest difference between two distinct numbers that can be represented. In practical terms, it is the smallest fraction or number that, when added to or subtracted from a large number, results in a calculable change. This rounding unit is also often referred to as machine epsilon.
MATLAB Programming
MATLAB is a powerful computing environment often used for solving mathematical problems, including numerical analyses related to the IEEE floating point system. It offers robust features for implementing algorithms that can accurately determine machine epsilon, like the one described in the exercise.
In the MATLAB script given, the 'while' loop is fundamental to determining the rounding unit. It works by continuously halving the value of 'small_number' and adding it to 'large_number' until the sum differs from the original value.
Using the 'fprintf' command, the script then outputs the found rounding unit. This showcases MATLAB's capabilities in handling precision and performing iterative calculations efficiently, making it a valuable tool for developers and engineers striving to understand the behavior of floating point arithmetic.
Numerical Analysis
Numerical analysis is the branch of mathematics that explores how numerical computations can be conducted efficiently and accurately. Understanding concepts like rounding units and machine epsilon is essential in this field, as they directly impact the precision and possible errors in computational algorithms.
Rounding errors in floating point computations occur because not all numbers can be represented exactly. This introduces small errors in arithmetic operations which, if not managed well, can accumulate and significantly impact results.
In practical terms, numerical analysis concerns itself with gauging these errors and optimizing computations to minimize their impact. Tasks like calculating derivatives or integrals numerically often rely on knowing the rounding unit, as it determines how closely we can approximate real numbers and functions in our computations.
Utilizing MATLAB and adhering to IEEE standards allows numerically intensive tasks to be handled with better precision, ensuring accurate and reliable results across a variety of scientific and engineering applications.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) The number \(\frac{8}{7}=1.14285714285714 \ldots\) obviously has no exact representation in any decimal floating point system \((\beta=10)\) with finite precision \(t\). Is there a finite floating point system (i.e., some finite integer base \(\beta\) and precision \(t\) ) in which this number does have an exact representation? If yes, then describe such a system. (b) Answer the same question for the irrational number \(\pi\).

Write a quadratic equation solver. Your MATLAB script should get \(a, b, c\) as input, and accurately compute the roots of the corresponding quadratic equation. Make sure to check end cases such as \(a=0\), and consider ways to avoid an overflow and cancellation errors. Implement your algorithm and demonstrate its performance on a few cases (for example, the cases mentioned in Exercise 15). Show that your algorithm produces better results than the standard formula for computing roots of a quadratic equation.

In the statistical treatment of data one often needs to compute the quantities $$ \bar{x}=\frac{1}{n} \sum_{i=1}^{n} x_{i}, \quad s^{2}=\frac{1}{n} \sum_{i=1}^{n}\left(x_{i}-\bar{x}\right)^{2}, $$ where \(x_{1}, x_{2}, \ldots, x_{n}\) are the given data. Assume that \(n\) is large, say, \(n=10,000\). It is easy to see that \(s^{2}\) can also be written as $$ s^{2}=\frac{1}{n} \sum_{i=1}^{n} x_{i}^{2}-\bar{x}^{2} $$ (a) Which of the two methods to calculate \(s^{2}\) is cheaper in terms of overall computational cost? Assume \(\bar{x}\) has already been calculated and give the operation counts for these two options. (b) Which of the two methods is expected to give more accurate results for \(s^{2}\) in general? (c) Give a small example, using a decimal system with precision \(t=2\) and numbers of your choice, to validate your claims.

Suppose a computer company is developing a new floating point system for use with their machines. They need your help in answering a few questions regarding their system. Following the terminology of Section \(2.2\), the company's floating point system is specified by \((\beta, t, L, U) .\) Assume the following: \- All floating point values are normalized (except the floating point representation of zero). \- All digits in the mantissa (i.e., fraction) of a floating point value are explicitly stored. \- The number 0 is represented by a float with a mantissa and an exponent of zeros. (Don't worry about special bit patterns for \(\pm \infty\) and NaN.) Here is your part: (a) How many different nonnegative floating point values can be represented by this floating point system? (b) Same question for the actual choice \((\beta, t, L, U)=(8,5,-100,100)\) (in decimal) which the company is contemplating in particular. (c) What is the approximate value (in decimal) of the largest and smallest positive numbers that can be represented by this floating point system? (d) What is the rounding unit?

Consider the approximation to the first derivative $$ f^{\prime}(x) \approx \frac{f(x+h)-f(x)}{h} $$ The truncation (or discretization) error for this formula is \(\mathcal{O}(h)\). Suppose that the absolute error in evaluating the function \(f\) is bounded by \(\varepsilon\) and let us ignore the errors generated in basic arithmetic operations. (a) Show that the total computational error (truncation and rounding combined) is bounded by $$ \frac{M h}{2}+\frac{2 \varepsilon}{h}, $$ where \(M\) is a bound on \(\left|f^{\prime \prime}(x)\right|\). (b) What is the value of \(h\) for which the above bound is minimized? (c) The rounding unit we employ is approximately equal to \(10^{-16}\). Use this to explain the behavior of the graph in Example \(1.3\). Make sure to explain the shape of the graph as well as the value where the apparent minimum is attained. (d) It is not difficult to show, using Taylor expansions, that \(f^{\prime}(x)\) can be approximated more accurately (in terms of truncation error) by $$ f^{\prime}(x) \approx \frac{f(x+h)-f(x-h)}{2 h} $$ For this approximation, the truncation error is \(\mathcal{O}\left(h^{2}\right)\). Generate a graph similar to Figure \(1.3\) (please generate only the solid line) for the same function and the same value of \(x\), namely, for \(\sin (1.2)\), and compare the two graphs. Explain the meaning of your results.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free