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The IEEE 754 (known as the floating point standard) specifies the 128 -bit word as having 15 bits for the exponent. What is the length of the fraction? What is the rounding unit? How many significant decimal digits does this word have? Why is quadruple precision more than twice as accurate as double precision, which is in turn more than twice as accurate as single precision?

Short Answer

Expert verified
Answer: Quadruple precision (128-bit) provides higher accuracy than double precision (64-bit) and single precision (32-bit) due to the increased number of bits allocated for the fraction. Quadruple precision has 112 bits for the fraction (approximately 34 significant decimal digits of accuracy), while double precision has 52 bits for the fraction (about 16 decimal digits of accuracy), and single precision has 23 bits for the fraction (about 7 decimal digits of accuracy).

Step by step solution

01

Understand the IEEE 754 floating-point representation

In the IEEE 754 floating-point standard, a number is represented using a sign, exponent, and fraction (also called significand or mantissa). For quadruple precision (128-bit) numbers, the representation is as follows: 1 bit for the sign, 15 bits for the exponent, and the remaining bits for the fraction.
02

Calculate the length of the fraction

For 128 bits, 1 bit is reserved for the sign and 15 bits for the exponent. Therefore, the length of the fraction for quadruple precision is 128 - 1 (sign bit) - 15 (exponent bits) = 112 bits.
03

Calculate the rounding unit

The rounding unit, also known as machine epsilon, is the smallest number that can be added to 1 (in the same floating-point format) to give a different number. For quadruple precision, we can calculate the rounding unit using: rounding unit = \(2^{-p}\), where p is the number of bits in the fraction. So, rounding unit = \(2^{-112}\) ≈ \(2.16 * 10^{-34}\)
04

Calculate the significant decimal digits

We can calculate the number of significant decimal digits using: decimal digits = p * log10(2), where p is the number of bits in the fraction. So, significant decimal digits ≈ 112 * log10(2) ≈ 33.7 Therefore, the 128-bit word has approximately 34 significant decimal digits.
05

Explain the accuracy of quadruple precision

Quadruple precision is more than twice as accurate as double precision since it has more bits for the fraction. As the number of bits in the fraction increases, the precision, or the number of significant decimal digits, increases. This allows for a higher level of accuracy when representing numbers in the quadruple precision format. Similarly, double precision has more bits for the fraction than single precision, thus providing higher accuracy as well. Comparatively, quadruple precision has 112 bits for the fraction, double precision has 52 bits for the fraction (about 16 decimal digits), and single precision has 23 bits for the fraction (about 7 decimal digits).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Floating-Point Precision
In computer science, floating-point precision refers to the accuracy with which a computer can represent and process real numbers. This is crucial for computations that require significant detail, such as scientific calculations and graphics rendering. The IEEE 754 standard establishes the format and precision levels for representing floating-point numbers. It specifies several levels of precision, namely single, double, and quadruple precision.
  • Single Precision: Uses 32 bits, allowing for approximately 7 significant decimal digits.
  • Double Precision: Uses 64 bits, giving around 16 significant decimal digits.
  • Quadruple Precision: Uses 128 bits, providing approximately 34 significant decimal digits.
As we increase the number of bits in a floating-point representation, we gain the ability to represent numbers more precisely, which reduces rounding errors in calculations.
Significant Decimal Digits
Significant decimal digits are a way of expressing how precisely we can represent real numbers in a given floating-point format. Essentially, this measures the number of digits in a number that contribute meaningfully to its expression. For example, in quadruple precision, which uses 128 bits, we can achieve around 34 significant decimal digits.
This is calculated by multiplying the number of bits in the fraction (112 bits for quadruple precision) by the logarithm of 2, i.e., \[\text{decimal digits} = p \times \log_{10}(2)\],where \( p \) is the number of fraction bits. This precision allows for very detailed numerical representations, reducing error in computations.
Machine Epsilon
Machine epsilon, often called the rounding unit, is crucial in understanding the limits of precision in floating-point representations. It is defined as the smallest difference between 1 and the next representable number greater than 1. In the context of quadruple precision:\[\text{Machine epsilon} = 2^{-112}\]This equates to approximately \(2.16 \times 10^{-34}\), a very small number indicating the fine granularity available in numerical calculations. Understanding machine epsilon helps in determining the potential for rounding errors in calculations and in setting tolerances when designing numerical algorithms.
Fraction Length
Fraction length, also known as the significand or mantissa, is an essential component of floating-point representation. It dictates the number of bits allocated for the significand part of a floating-point number. In quadruple precision:
  • A total of 112 bits are used for the fraction.
This allocation allows the representation of a wide range of fractions, contributing to the overall precision of the format. A longer fraction length implies more detail can be stored within the numeric representation, leading to higher precision and smaller rounding errors in computations.
Quadruple Precision
Quadruple precision is a floating-point representation format defined by the IEEE 754 standard as using 128 bits. It consists of:
  • 1 bit for the sign.
  • 15 bits for the exponent.
  • 112 bits for the fraction.
Quadruple precision offers an increased accuracy and precision over double and single precision formats, with about 34 significant decimal digits. It's particularly suitable for complex simulations, scientific computations, and any scenario where minute differences can vastly impact results. This enhanced precision ensures minimal loss of data and fewer rounding errors during arithmetic operations. The primary advantage lies in its ability to represent very small numbers and very large numbers with a high level of accuracy.

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Most popular questions from this chapter

(a) How many distinct positive numbers can be represented in a floating point system using base \(\beta=10\), precision \(t=2\) and exponent range \(L=-9, U=10 ?\) (Assume normalized fractions and don't worry about underflow.) (b) How many normalized numbers are represented by the floating point system \((\beta, t, L, U) ?\) Provide a formula in terms of these parameters.

Suppose a computer company is developing a new floating point system for use with their machines. They need your help in answering a few questions regarding their system. Following the terminology of Section \(2.2\), the company's floating point system is specified by \((\beta, t, L, U) .\) Assume the following: \- All floating point values are normalized (except the floating point representation of zero). \- All digits in the mantissa (i.e., fraction) of a floating point value are explicitly stored. \- The number 0 is represented by a float with a mantissa and an exponent of zeros. (Don't worry about special bit patterns for \(\pm \infty\) and NaN.) Here is your part: (a) How many different nonnegative floating point values can be represented by this floating point system? (b) Same question for the actual choice \((\beta, t, L, U)=(8,5,-100,100)\) (in decimal) which the company is contemplating in particular. (c) What is the approximate value (in decimal) of the largest and smallest positive numbers that can be represented by this floating point system? (d) What is the rounding unit?

The function \(f_{1}(x, \delta)=\cos (x+\delta)-\cos (x)\) can be transformed into another form, \(f_{2}(x, \delta)\), using the trigonometric formula $$ \cos (\phi)-\cos (\psi)=-2 \sin \left(\frac{\phi+\psi}{2}\right) \sin \left(\frac{\phi-\psi}{2}\right) . $$ Thus, \(f_{1}\) and \(f_{2}\) have the same values, in exact arithmetic, for any given argument values \(x\) and \(\delta\). (a) Show that, analytically, \(f_{1}(x, \delta) / \delta\) or \(f_{2}(x, \delta) / \delta\) are effective approximations of the function \(-\sin (x)\) for \(\delta\) sufficiently small. (b) Derive \(f_{2}(x, \delta)\). (c) Write a MATLAB script which will calculate \(g_{1}(x, \delta)=f_{1}(x, \delta) / \delta+\sin (x)\) and \(g_{2}(x, \delta)=\) \(f_{2}(x, \delta) / \delta+\sin (x)\) for \(x=3\) and \(\delta=1 . \mathrm{e}-11 .\) (d) Explain the difference in the results of the two calculations.

In the statistical treatment of data one often needs to compute the quantities $$ \bar{x}=\frac{1}{n} \sum_{i=1}^{n} x_{i}, \quad s^{2}=\frac{1}{n} \sum_{i=1}^{n}\left(x_{i}-\bar{x}\right)^{2}, $$ where \(x_{1}, x_{2}, \ldots, x_{n}\) are the given data. Assume that \(n\) is large, say, \(n=10,000\). It is easy to see that \(s^{2}\) can also be written as $$ s^{2}=\frac{1}{n} \sum_{i=1}^{n} x_{i}^{2}-\bar{x}^{2} $$ (a) Which of the two methods to calculate \(s^{2}\) is cheaper in terms of overall computational cost? Assume \(\bar{x}\) has already been calculated and give the operation counts for these two options. (b) Which of the two methods is expected to give more accurate results for \(s^{2}\) in general? (c) Give a small example, using a decimal system with precision \(t=2\) and numbers of your choice, to validate your claims.

Write a MATLAB program that (a) sums up \(1 / n\) for \(n=1,2, \ldots, 10,000\); (b) rounds each number \(1 / n\) to 5 decimal digits and then sums them up in 5 -digit decimal arithmetic for \(n=1,2, \ldots, 10,000 ;\) (c) sums up the same rounded numbers (in 5 -digit decimal arithmetic) in reverse order, i.e., for \(n=10,000, \ldots, 2,1\). Compare the three results and explain your observations. For generating numbers with the requested precision, you may want to do Exercise 6 first.

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