We can always find two linearly independent solutions in the form of a power series centered at
, that is, we can always find two linearly independent solutions in the form of a power series centered at
.
![]()
For the given differential equation, we must find two linearly independent series solutions. The first and second derivatives of (1) are found as follows:
The first and second derivatives of this power series solution are calculated first.
![]()
The summation's indices must now be shifted. We combine the summations when the indices of summation have the same beginning point and the powers of x agree.
![]()
We shall have y"-y'=0 for all x in some interval because the stated linear first order differential equation is y"-y'=0.
![]()
As a result, we must have the following as an identity.
or
, ![]()
We discover this by considering successive integer values of k starting with k=0.
![]()
![]()
![]()
![]()
and so on, with any values for
and
.
We derive a formal power series solution by utilizing the original solution form and the aforementioned results.
![]()
We rewrite the solution as
, here
![]()
![]()
Now, we know from the Maclaurin Series that the sum
is the expansion if
. As a result, we can simplify the solution once more as follows:
![]()
Let's use the method from section 4.3 to determine the solution:
is the auxiliary equation of the equation y"-y'=0. The roots of this equation are
and
after factoring and solving. As a result, the overall solution is;
![]()
It is the same as the general answer determined with
and
using the method of section 4.3.
![]()
![]()