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Consider the differential equation y'=y2+4

(a)Explain why there exist no constant solutions of the DE.

(b)Describe the graph of a solutiony=ϕ(x). For example, can a solution curve have any relative extrema?

(c)Explain whyy=0is the y-coordinate of a point of inflection of a solution curve.

(d)Sketch the graph of a solutiony=ϕ(x)of the differential equation whose shape is suggested by parts (a) -(c).

Short Answer

Expert verified

a. Proved

b. A solution curve has no relative extrema.

c. Proved

d. The graph is drawn below

Step by step solution

01

Definition of Ordinary Differential Equation

A system of ordinary differential equations is two or more equations involving the derivatives of two or more unknown functions of a single independent variable.

02

Compute Differentiation

a.

Given Suppose y'=y2+4.is a constant solution.

Then we have both that y'=c'=0and y'=c2+4>0, a contradiction.

Therefore there are no constant solutions.

03

Describe the graph solution

b.

Note that if y=ϕxis a solution we have that ϕ'=ϕ(x)2+4>0, so the graph of is monotonously increasing for all x. In particular a solution has no relative extrema.

Therefore, a solution curve has no relative extrema.

04

Point of inflection of a solution curve

c.

For a solution y=ϕxwe have that ϕ''x=y''=y2+4'=2ywhich changes sign at y=0,

Therefore the y-coordinate of a point of inflection of a solution curve is always 0.

05

Graph for the equation

d.

From the previous items, the graph of a solution ϕxto this DE should be something like the graph bellow:

Hence, this isthe graph of a solutiony=ϕ(x)of the differential equation whose shape is suggested by parts (a) -(c).

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