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In Problems 1-16 the indicated function y1(x)is a solution of the given differential equation. Use reduction of order or formula (5), as instructed, to find a second solution y2(x)

y''+9y=0;y1=sin3x

Short Answer

Expert verified

The second solution of the given differential equation is cos3x

Step by step solution

01

Definition of Reduction of order

  • Reduction of order is a method for solving second-order linear ordinary differential equations in mathematics.
  • When one solution is known and a second linearly independent solution is sought, this method is used.
  • The approach can be used to solve n-th order equations as well.
  • y2=y1(x)e-P(x)dxy12(x)dx
02

Find the second solution

The second order differential equation

y''+9y=0

as the form

y''+p(x)y'+q(x)y=0,then we havep(x)=0andq(x)=9,

with a first solution y1(x)=sin3x, and we have to obtain the second solution using the formula of reduction of order as

y2(x)=y1(x)e-p(x)dxy12dx=sin3xe-0dx(sin3x)2dx=sin3xksin23xdx=sin3xkcsc23xdx=sin3x×k×13cot3x=k3sin3x×cos3xsin3x=k3cos3x=c2cos3x=cos3x

Then, the second solution of the given differential equationy''+9y=0 , where c2=k3 and we let it equal 1 .

Therefore, the second solution of the given differential equation is cos3x

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