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The sine integral function is defined as Si(x)=0xsinttdt, where the integrand is defined to be 1 at x = 0. See Appendix A. Express the solution of the initial-value problem

x3dydx+2x2y=10sinx,y(1)=0 in terms of Si(x)

Short Answer

Expert verified

So, the solution of initial problem isy(x)=10x-2[Si(x)-Si(1)].

Step by step solution

01

Form of linear equation

The linear differential equation is of the form dydx+Py=Q, where P and Q are numeric constants or functions in x.

02

Evaluation

The given differential equation, can be written as

dydx+2xy=10x3sinx

Linear differential equation of the first order

localid="1668416535098" y'+P(x)y=f(x)

Based on (1) and 2the given differential equation, we obtain

localid="1668416542753" P(x)=2xandf(x)=10x3sinx

03

Find integrated factor

The integrating factor is given by

eP(x)dx

Use the formula (3), to get integrating factor

role="math" localid="1664272742192" =e21xdx=e2ln|x|=elnx2=x2Thus,thesolutionisyx2=0x10t2t3sintdt+c

04

Find the value of constant

y=x-2100xsinttdt+cx-2Si(x)=0zsintty=x-210Si(x)+cx-2

Use the initial condition y(1) = 0, to get c.

0=10Si(1)+cc=-10Si(1)

Substitute the value in the equation (4).

y(x)=10x-2[Si(x)-Si(1)]

So, the required solution is y(x)=10x-2[Si(x)-Si(1)].

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