Chapter 17: Problem 21
Suppose \(2_{R} \in R^{*}\) and \(\omega \in R\) is a primitive \(2^{n}\) th root of unity. (a) Let \(k\) be any integer, and consider gcd \(\left(k, 2^{n}\right),\) which must be of the form \(2^{m}\) for some \(m=0, \ldots, n .\) Show that \(\omega^{k}\) is a primitive \(2^{n-m}\) th root of unity. (b) Show that if \(n \geq 1,\) then \(\omega-1_{R} \in R^{*}\) (c) Show that \(\omega^{k}-1_{R} \in R^{*}\) for all integers \(k \not \equiv 0\left(\bmod 2^{n}\right)\). (d) Show that for every integer \(k,\) we have $$ \sum_{i=0}^{2^{n}-1} \omega^{k i}=\left\\{\begin{array}{ll} 2_{R}^{n} & \text { if } k \equiv 0\left(\bmod 2^{n}\right) \\ 0_{R} & \text { if } k \neq 0\left(\bmod 2^{n}\right) \end{array}\right. $$ (e) Let \(M_{2}\) be the 2 -multiplication map on \(R^{\times 2^{n}},\) which is a bijective, \(R\) -linear map. Show that $$ \mathcal{E}_{n, \omega} \circ \mathcal{E}_{n, \omega^{-1}}=\boldsymbol{M}_{2}^{n}=\mathcal{E}_{n, \omega^{-1}} \circ \mathcal{E}_{n, \omega} $$ and conclude that \(\mathcal{E}_{n, \omega}\) is bijective, with \(M_{2}^{-n} \circ \mathcal{E}_{n, \omega^{-1}}\) being its inverse. Hint: write down the matrices representing the maps \(\mathcal{E}_{n, \omega}\) and \(\mathcal{E}_{n, \omega^{-1}}\).
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.