Question

Let \(\rho: M \rightarrow M^{\prime}\) be a surjective \(R\) -linear map. Let \(S\) be the set of all submodules of \(M\) that contain \(\operatorname{Ker} \rho,\) and let \(S^{\prime}\) be the set of all submodules of \(M^{\prime} .\) Show that the sets \(S\) and \(\mathcal{S}^{\prime}\) are in one-to-one correspondence, via the map that sends \(N \in S\) to \(\rho(N) \in \mathcal{S}^{\prime}\).

Short answer

Question: Show that there is a one-to-one correspondence between the set of submodules in \(M\) that contain \(\operatorname{Ker} \rho\) and the set of all submodules in \(M^{\prime}\), where \(\rho: M \rightarrow M^{\prime}\) is a surjective \(R\)-linear map. Answer: Define the map \(\phi: S \rightarrow S^{\prime}\) by \(\phi(N) = \rho(N)\). This map is well-defined, injective, and surjective, establishing a one-to-one correspondence between the sets \(S\) and \(S^{\prime}\).

Step-by-step solution

Define the map

Define the map \(\phi: S \rightarrow S^{\prime}\) by \(\phi(N) = \rho(N)\) for all \(N \in S\).

Prove that \(\phi\) is well-defined

First, we need to prove that \(\phi(N)\) is indeed a submodule of \(M^{\prime}\). Let \(N \in S\). Since \(N\) is a submodule of \(M\) and \(\rho\) is an \(R\)-linear map, then \(\rho(N)\) is a submodule of \(M^{\prime}\) by applying the homomorphism of abelian groups property. Thus, \(\phi\) is well-defined.

Prove injectivity

Suppose that \(\phi(N_1) = \phi(N_2)\) for some \(N_1, N_2 \in S\). Then, \(\rho(N_1) = \rho(N_2)\). Since \(\rho\) is surjective, it establishes that \(N_1 = N_2\), and so \(\phi\) is an injective map.

Prove surjectivity

Let \(Q \in S^{\prime}\). We want to show that there exists some \(N \in S\) such that \(\phi(N) = Q\). Let \(N = \{m \in M \mid \rho(m) \in Q\}\). From the properties of submodules and \(\rho\) being an \(R\)-linear map, it follows that \(N\) is a submodule of \(M\) containing \(\operatorname{Ker} \rho\), and hence \(N \in S\). Moreover, \(\rho(N) = Q\), which implies that \(\phi(N) = Q\). Therefore, \(\phi\) is a surjective map.

Conclude

Since the map \(\phi: S \rightarrow S^{\prime}\) is both injective and surjective, it is a one-to-one correspondence between the sets \(S\) and \(S^{\prime}\). This completes the proof.

Key concepts

R-linear map

In mathematics, particularly in module theory, an \(R\)-linear map is a fundamental concept that helps us understand the structure of modules over a ring \(R\). An \(R\)-linear map, similar to a linear transformation in vector spaces, is a function \( \rho: M \rightarrow M' \) between two modules \(M\) and \(M'\) that respects the module operations.

Key properties of an \(R\)-linear map include:

• Preservation of Addition: For any elements \(m_1, m_2 \in M\), we have \( \rho(m_1 + m_2) = \rho(m_1) + \rho(m_2) \).
• Scalar Multiplication: For any element \(m \in M\) and scalar \(r \in R\), the relation \( \rho(r \, m) = r \, \rho(m) \) holds.

This ensures that the structure of the module is maintained under the map. If the \(R\)-linear map is surjective, each element of \(M'\) is the image of some element in \(M\).

This property is crucial in module theory, making \(R\)-linear maps valuable tools for transferring information between different modules and exploring their properties.

submodules

Submodules are an important aspect of module theory similar to subspaces in linear algebra. A submodule \(N\) of a module \(M\) is a subset that is closed under the module operations, specifically:

• Closure under Addition: For any elements \(n_1, n_2 \in N\), we have \(n_1 + n_2 \in N\).
• Closure under Scalar Multiplication: For any element \(n \in N\) and scalar \(r \in R\), it satisfies \(r \, n \in N\).

The concept of submodules allows us to understand the internal structure within modules. In the context of the exercise, each submodule of \(M\) containing the kernel of the map \(\rho\) is part of the set \(S\). This inclusion condition ensures that any change within the kernel is reflected in the submodule, maintaining correspondence through \(\rho\).

Submodules enable us to decompose modules into smaller, more manageable pieces, much like how we analyze vector spaces using subspaces. It offers an insight into how the larger structures of modules are constructed from simpler, well-understood components.

kernel of homomorphism

The kernel of a homomorphism is a key concept in understanding structure-preserving maps, such as \(R\)-linear maps in module theory. The kernel of a homomorphism \(\rho: M \rightarrow M'\) is the set of all elements in \(M\) that are mapped to the zero element in \(M'\). Mathematically, it is defined as:

\[\operatorname{Ker}(\rho) = \{ m \in M \mid \rho(m) = 0 \}\]

Key properties include:

• Submodule Status: The kernel is always a submodule of \(M\), meaning it satisfies closure under addition and scalar multiplication.
• Detecting Injectivity: If \(\operatorname{Ker}(\rho) = \{ 0 \}\), then \(\rho\) is injective, meaning distinct elements in \(M\) map to distinct elements in \(M'\).

The kernel provides insight into the structure and behavior of homomorphisms. In exercises, identifying the kernel helps determine whether mappings are injective, and it plays a crucial role in exploring the relation between submodules \(S\) and \(S'\) as described in the exercise. Kernels also help in forming quotient modules, by dividing out the kernel from the original module, which is essential in understanding the image of \(M\) within \(M'\).