Chapter 8: Problem 9
Consider the potential outcomes framework, where \(w\) is a binary treatment indicator and the potential outcomes are \(y(0)\) and \(y(1) .\) Assume that \(w\) is randomly assigned, so that \(w\) is independent of \([y(0), y(1)] .\) Let \(\mu_{0}=\mathrm{E}[y(0)], \mu_{1}=\mathrm{E}[y(1)], \sigma_{0}^{2}=\operatorname{Var}[y(0)],\) and \(\sigma_{1}^{2}=\operatorname{Var}[y(1)]\). i. Define the observed outcome as \(y=(1-w) y(0)+w y(1) .\) Letting \(\tau=\mu_{1}-\mu_{0}\) be the average treatment effect, show you can write $$y=\mu_{0}+\tau w+(1-w) v(0)+w v(1)$$ where \(v(0)=y(0)-\mu_{0}\) and \(v(1)=y(1)-\mu_{1}\) ii. Let \(u=(1-w) v(0)+w v(1)\) be the error term in $$y=\mu_{0}+\tau w+u$$ Show that $$\mathbf{E}(u | w)=0$$ What statistical properties does this finding imply about the OLS estimator of \(\tau\) from the simply regression \(y_{i}\) on \(w_{i}\) for a random sample of size \(n\) ? What happens as \(n \rightarrow \infty ?\) iii. Show that $$\operatorname{Var}(u | w)=\mathrm{E}\left(u^{2} | w\right)=(1-w) \sigma_{0}^{2}+w \sigma_{1}^{2}$$ Is there generally heteroskedasticity in the error variance? iv. If you think \(\sigma_{1}^{2} \neq \sigma_{0}^{2},\) and \(\hat{\tau}\) is the OLS estimator, how would you obtain a valid standard error for \(7 ?\) v. After obtaining the OLS residuals, \(\widehat{u}_{i}, i=1, \ldots, n,\) propose a regression that allows consistent estimation of \(\sigma_{0}^{2}\) and \(\sigma_{1}^{2}\). [Hint: You should first square the residuals.]
Short Answer
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