Chapter 4: Problem 7
In Example 4.7 . we used data on nonunionized manufacturing firms to estimate the relationship between the scrap rate and other firm characteristics. We now look at this example more closely and use all available firms. i. The population model estimated in Example 4.7 can be written as $$\log (\operatorname{scrap})=\beta_{0}+\beta_{1} \text {hrsemp}+\beta_{2} \log (\text {sales})+\beta_{3} \log (\text {employ})+u$$ Using the 43 observations available for 1987 , the estimated equation is $$\begin{aligned} \widehat{\log (\text {scrap})}=& 11.74-.042 \text { hrsemp}-.951 \log (\text {sales})+.992 \log (\text {employ}) \\ &(4.57)(.019) \\ n=& 43, R^{2}=.310 \end{aligned}$$ Compare this equation to that estimated using only the 29 nonunionized firms in the sample. ii. Show that the population model can also be written as $$\log (s c r a p)=\beta_{0}+\beta_{1} h r s e m p+\beta_{2} \log (s a l e s / e m p l o y)+\theta_{3} \log (e m p l o y)+u$$ where \(\left.\theta_{3}=\beta_{2}+\beta_{3} . \text { [Hint: Recall that } \log \left(x_{2} / x_{3}\right)=\log \left(x_{2}\right)-\log \left(x_{3}\right) .\right]\) Interpret the hypothesis \(\mathrm{H}_{0}: \theta_{3}=0\) iii. When the equation from part (ii) is estimated, we obtain $$\begin{aligned} \widehat{\log (\text {scrap})}=& 11.74-.042 \text { hrsemp}-.951 \log (\text {sales/employ})+.041 \log (\text {employ}) \\ &(4.57)(.019) \\ n=& 43, R^{2}=.310 \end{aligned}$$ Controlling for worker training and for the sales-to-employee ratio, do bigger firms have larger statistically significant scrap rates? iv. Test the hypothesis that a \(1 \%\) increase in sales/employ is associated with a \(1 \%\) drop in the scrap rate.
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