Chapter 7: Problem 3
A theoretical estimate of the strength of a crystalline solid is its binding energy per unit volume. Evaluate the strength of forsterite if its binding energy is \(10^{3} \mathrm{~kJ} \mathrm{~mol}^{-1}\) and its mean atomic volume is \(6.26 \times 10^{-6} \mathrm{~m}^{3} \mathrm{~mol}^{-1}\). The presence of grain boundaries and dislocations weakens a crystalline solid considerably below its theoretical strength.
Short Answer
Step by step solution
Understand the Problem
Identify Known Values
Convert Binding Energy to Joules
Calculate Theoretical Strength
Interpret the Result
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Binding Energy
For forsterite, the binding energy is given as \(10^3 \text{ kJ mol}^{-1}\). This value represents the total amount of energy needed to break the bonds holding the individual atoms together in the solid lattice.
- A high binding energy indicates strong bonds within the material, contributing to its overall robustness.
- Binding energy is often measured in kilojoules per mole (kJ/mol), but converting it to joules (J) is a common practice to align with scientific calculations.
- In the problem at hand, converting \(10^3 \text{ kJ mol}^{-1}\) to \(10^6 \text{ J mol}^{-1}\) helps in using consistent units for further calculations.
Mean Atomic Volume
In our example, the mean atomic volume for forsterite is \(6.26 \times 10^{-6} \text{ m}^3 \text{ mol}^{-1}\). This metric is significant when calculating the material's theoretical strength.
- Mean atomic volume allows us to understand the spatial arrangement and the density of atoms within the crystal.
- The smaller the atomic volume, the tighter the atoms are packed, and often, this correlates with stronger materials.
- This volume is utilized as the denominator in the theoretical strength calculation because it gives the context of energy binding per unit space in a material.
Theoretical Strength
For forsterite, the theoretical strength is calculated as \(\frac{10^6 \text{ J mol}^{-1}}{6.26 \times 10^{-6} \text{ m}^3 \text{ mol}^{-1}} = 1.60 \times 10^{11} \text{ J m}^{-3}\), representing the upper limit of its strength.
- Theoretical strength assumes no defects like dislocations or grain boundaries, portraying the ideal scenario.
- This calculated limit is often higher than the practical strength due to the presence of real-world imperfections.
- Understanding this strength helps in designing materials and predicting their behavior under stress.
Grain Boundaries
In crystalline solids like metals and minerals, grain boundaries can weaken the material's strength when compared to its theoretical maximum.
- Grain boundaries often act as barriers to dislocation motion, which can advantageously strengthen or disadvantageously weaken a material depending on the context.
- They can also contribute to the scattering of free electrons in conductors, impacting electrical properties.
- The manipulation of grain boundaries is a key strategy in materials science to develop stronger and more reliable materials.
Dislocations
These imperfections allow crystals to deform more easily under stress, thus reducing their theoretical strength.
- A dislocation can move across the grains, allowing the layers of atoms to slip past each other, leading to material deformation.
- This movement is what enables metals to be shaped and bent without breaking, making dislocations useful despite their weakening effect.
- Material scientists strive to control the behavior and density of dislocations to optimize mechanical properties.