Chapter 7: Problem 10
Show that the effective viscosity \(\mu_{\text {eff }}\) for the channel flow of a power-law fluid is given by $$ \mu_{\mathrm{eff}} \equiv \frac{\tau}{d u / d y}=\left(\frac{p_{1}-p_{0}}{L}\right) \frac{h^{2}}{4(n+2) \bar{u}}\left(\frac{2 y}{h}\right)^{1-n} $$ or $$ \frac{\mu_{\text {eff }}}{\mu_{\text {eff, wall }}}=\left(\frac{2 y}{h}\right)^{1-n} $$ where \(\mu_{\text {eff,wall }}\) is the value of \(\mu_{\text {eff }}\) at \(y=\pm h / 2\). Plot \(\mu_{\text {eff }} / \mu_{\text {eff, wall as a function of }} y / h\) for \(n=1,3\), and 5 .
Short Answer
Step by step solution
Understand the Problem
Define Key Variables and Equations
Derive Expression for Effective Viscosity \(\mu_{\text{eff}}\)
Calculate \(\mu_{\text{eff}}/\mu_{\text{eff, wall}}\)
Simplify and Verify Expression
Plot \(\mu_{\text{eff}}/\mu_{\text{eff, wall}}\) vs \(y/h\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Effective Viscosity
Power-Law Fluid Dynamics
- If \( n = 1 \, \) the fluid behaves like a Newtonian fluid (constant viscosity).
- If \( n < 1 \, \) the fluid is pseudoplastic (shear-thinning).
- If \( n > 1 \, \) the fluid is dilatant (shear-thickening).