Chapter 5: Problem 2
Determine the ratio of the centrifugal acceleration to the gravitational acceleration at the Earth's equator.
Short Answer
Expert verified
The ratio of centrifugal acceleration to gravitational acceleration at the Earth's equator is approximately 0.0035.
Step by step solution
01
Understanding the Formula for Centrifugal Acceleration
At the Earth's equator, an object experiences centrifugal acceleration due to the Earth's rotation. The formula for centrifugal acceleration is given by \( a_c = \frac{v^2}{r} \), where \( v \) is the tangential velocity and \( r \) is the radius of Earth at the equator. Another expression for this is \( a_c = \omega^2 r \), where \( \omega \) is the angular velocity.
02
Calculating Angular Velocity
The angular velocity \( \omega \) of the Earth can be calculated from the fact that the Earth makes one full rotation (\( 2\pi \) radians) in about 24 hours. Thus, \( \omega = \frac{2\pi}{24 \times 3600} \) rad/s, as there are 3600 seconds in an hour.
03
Determining the Earth's Radius at the Equator
The radius of the Earth at the equator is approximately 6378 kilometers. For our calculations, we convert this to meters, giving us \( r = 6378000 \) meters.
04
Calculating Centrifugal Acceleration
Using \( a_c = \omega^2 r \), we substitute in the values: \( a_c = \left(\frac{2\pi}{24 \times 3600}\right)^2 \times 6378000 \). Calculating this gives \( a_c \approx 0.034 \text{ m/s}^2 \).
05
Understanding Gravitational Acceleration
The gravitational acceleration \( g \) at Earth's surface is approximately \( 9.81 \text{ m/s}^2 \). This is the acceleration due to Earth's gravitational pull.
06
Calculating the Ratio
The ratio of centrifugal acceleration to gravitational acceleration is then given by \( \frac{a_c}{g} = \frac{0.034}{9.81} \), which simplifies to approximately 0.0035.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Gravitational Acceleration
Gravitational acceleration, denoted as \( g \), is the acceleration experienced by an object due to the gravitational pull of the Earth. On the surface of the Earth, this acceleration is approximately \( 9.81 \text{ m/s}^2 \). It acts downwards, towards the center of the Earth.
Gravitational acceleration is a constant value that affects everything near the Earth equally, regardless of its mass. This means that if you drop two objects from the same height, they will reach the ground at the same time, as long as air resistance is negligible.
Key points about gravitational acceleration:
Gravitational acceleration is a constant value that affects everything near the Earth equally, regardless of its mass. This means that if you drop two objects from the same height, they will reach the ground at the same time, as long as air resistance is negligible.
Key points about gravitational acceleration:
- It is responsible for keeping objects grounded.
- Its value varies slightly depending on where you are on Earth due to factors like altitude.
- It's crucial in calculations involving free-fall and projectile motion.
Earth's Rotation
Earth's rotation refers to the spinning of the Earth around its own axis. This rotation occurs from west to east and is responsible for the cycle of day and night.
The Earth completes one full rotation approximately every 24 hours. As it rotates, different parts of the globe experience sunlight, creating the day-night pattern.
The rotational motion of the Earth induces some effects worth noting:
The Earth completes one full rotation approximately every 24 hours. As it rotates, different parts of the globe experience sunlight, creating the day-night pattern.
The rotational motion of the Earth induces some effects worth noting:
- Cyclical patterns: Understanding Earth's rotation is essential for grasping day length and time zones.
- Rotational speed: At the equator, Earth rotates at about 1670 kilometers/hour. This speed contributes to the phenomena like centrifugal acceleration.
- Coriolis effect: It's responsible for the deflection of objects due to Earth's rotation, which affects weather patterns and ocean currents.
Angular Velocity
Angular velocity \( \omega \) represents how fast an object rotates or revolves relative to another point, usually in terms of radians per second. For Earth, angular velocity is linked to its rotation.
To calculate Earth's angular velocity, we note that it completes a full turn or rotation (equal to \( 2\pi \) radians) in 24 hours. Therefore, the angular velocity of Earth can be mathematically expressed as:
\[ \omega = \frac{2\pi}{24 \times 3600} \text{ radians/second} \]
Feel free to perform this calculation to find its precise value.
Important points about angular velocity:
To calculate Earth's angular velocity, we note that it completes a full turn or rotation (equal to \( 2\pi \) radians) in 24 hours. Therefore, the angular velocity of Earth can be mathematically expressed as:
\[ \omega = \frac{2\pi}{24 \times 3600} \text{ radians/second} \]
Feel free to perform this calculation to find its precise value.
Important points about angular velocity:
- It differs from linear velocity because it describes rotation, not translation.
- Angular velocity is crucial for understanding rotational mechanics and phenomena like centrifugal forces.
- It connects seamlessly with other rotational formulas such as those for calculating centrifugal acceleration \( a_c \).