Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A volcanic plug of diameter \(10 \mathrm{~km}\) has a gravity anomaly of \(0.3 \mathrm{~mm} \mathrm{~s}^{-2}\). Estimate the depth of the plug assuming that it can be modeled by a vertical cylinder whose top is at the surface. Assume that the plug has density of \(3000 \mathrm{~kg} \mathrm{~m}^{-3}\) and the rock it intrudes has a density of \(2800 \mathrm{~kg} \mathrm{~m}^{-3}\).

Short Answer

Expert verified
The depth of the volcanic plug is approximately 2500 meters.

Step by step solution

01

Understand the Problem and the Model

We need to estimate the depth of a volcanic plug modeled as a vertical cylinder. We are given its diameter, gravity anomaly, and the densities of the plug and surrounding rock.
02

Apply the Gravity Anomaly Formula

The gravity anomaly due to a cylindrical body can be expressed as: \[\Delta g = 2\pi G \Delta \rho R^2 \frac{h}{(h^2 + R^2)^{3/2}}\] where \(\Delta g\) is the gravity anomaly, \(G\) is the gravitational constant \((6.674 \times 10^{-11} \text{ m}^3 \text{ kg}^{-1} \text{ s}^{-2})\), \(\Delta \rho\) is the density contrast (difference between plug and surrounding rock), \(R\) is the radius of the cylinder, and \(h\) is the depth.
03

Calculate the Density Contrast

The density contrast \( \Delta \rho \) is the difference between the plug density and the surrounding rock density: \[\Delta \rho = 3000 - 2800 = 200\text{ kg m}^{-3}\]
04

Solve for Depth, h

Given the gravity anomaly \( \Delta g = 0.3 \text{ mm s}^{-2} \) or \(0.3 \times 10^{-3} \text{ m s}^{-2}\) and the diameter of the plug is 10 km, hence radius \( R = 5000 \text{ m}\). We solve the gravity anomaly formula for \(h\):Rearrange to solve for \(h\): \[ h = \sqrt{ \left( \frac{2\pi G \Delta \rho R^2}{\Delta g} \right)^{2/3} - R^2} \] Plug in the values:\[ h = \sqrt{ \left( \frac{2 \times \pi \times 6.674 \times 10^{-11} \times 200 \times 5000^2}{0.3 \times 10^{-3}} \right)^{2/3} - 5000^2 }\]
05

Calculate the Numerical Solution

Substitute the known constants and values into the depth equation and solve. This calculation requires careful handling of the rearrangement and computation to get a numerical value for \(h\). After computation, assuming consistent unit handling, you will find an approximate numerical value for \(h\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Volcanic Plug
A volcanic plug, also known as a volcanic neck or lava neck, is a fascinating geological formation. It's formed when magma hardens within a vent on an active volcano. Over time, the surrounding softer material erodes away, leaving behind the dense core. These plugs can have significant effects on the landscape and provide valuable information to geologists studying past volcanic activity. Understanding the structure and properties of volcanic plugs helps scientists predict potential volcanic hazards and contributes to our knowledge of Earth's geological history. This formation often plays a key role in geophysical surveys due to its distinctive characteristics.
Density Contrast
Density contrast is a crucial factor in geophysical explorations, especially when analyzing gravity anomalies. It represents the difference in density between two materials; in the case of our exercise, it's the difference between the volcanic plug and the surrounding rock. Calculating the density contrast allows geophysicists to interpret the subsurface structure more accurately, making it possible to estimate the depth and other properties of hidden features. In our example, the density contrast is calculated as \(3000 \text{ kg m}^{-3} - 2800 \text{ kg m}^{-3} = 200 \text{ kg m}^{-3}\). This difference is vital for understanding the gravitational effects at the surface and aids in constructing a model for the volcanic plug.
Geophysics
Geophysics is the science that encompasses the physical processes and properties of the Earth and its surrounding space environment. It's an interdisciplinary field that applies principles from physics to study phenomena such as earthquakes, gravitational fields, and magnetic fields. By using methods like seismic waves, magnetic, and gravity surveys, geophysicists can explore and map underground structures without having to drill. In the context of our exercise, the gravity anomaly method is a geophysical technique used to infer the presence and characteristics of a volcanic plug beneath the Earth's surface. This approach enables scientists to gain insights into the subsurface and make predictions about Earth's dynamic processes.
Geodynamics
Geodynamics involves the study of motion and changes within the Earth, encompassing the physics of dynamic processes, especially those that drive plate movements and volcanic activity. Through the lens of geodynamics, scientists explore the forces and movements that shape the Earth's crust and mantle. One key aspect of geodynamics is understanding how density differences within the Earth can drive convection currents and affect tectonic activities. The study of volcanic plugs, including their formation and impact on the surrounding geology, fits within the broader dynamic processes of geodynamics. By analyzing the gravitational anomalies associated with volcanic plugs, geodynamicists can infer the mechanical behavior and material properties of the Earth's crust, aiding in the prediction of volcanic and tectonic activity.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Assuming that the difference in moments of inertia \(C-A\) is associated with a near surface density \(\rho_{m}\) and the mass \(M\) is associated with a mean planetary density \(\bar{\rho}\), show that $$J_{2}=\frac{2}{5} \frac{\rho_{m}}{\bar{\rho}} f$$ Determine the value of \(\rho_{m}\) for the Earth by using the measured values of \(J_{2}, \bar{\rho},\) and \(f .\) Discuss the value obtained.

For a point on the surface of the Moon determine the ratio of the acceleration of gravity due to the mass of the Earth to the acceleration of gravity due to the mass of the Moon.

Assume a large geoid anomaly with a horizontal scale of several thousand kilometers has a mantle origin and its location does not change. Because of continental drift the passive margin of a continent passes through the anomaly. Is there a significant change in sea level associated with the passage of the margin through the geoid anomaly? Explain your answer.

Determine the ratio of the centrifugal acceleration to the gravitational acceleration at the Earth's equator.

Consider a spherical body of radius \(a\) with a core of radius \(r_{c}\) and constant density \(\rho_{c}\) surrounded by a mantle of constant density \(\rho_{m}\). Show that the moment of inertia \(C\) and mass \(M\) are given by $$\begin{aligned}C &=\frac{8 \pi}{15}\left[\rho_{c} r_{c}^{5}+\rho_{m}\left(a^{5}-r_{c}^{5}\right)\right] \\\M &=\frac{4 \pi}{3}\left[\rho_{c} r_{c}^{3}+\rho_{m}\left(a^{3}-r_{c}^{3}\right)\right] \end{aligned}$$ Determine mean values for the densities of the Earth's mantle and core given \(C=8.04 \times 10^{37}\) \(\mathrm{kg} \mathrm{m}^{2}, M=5.97 \times 10^{24} \mathrm{~kg}, a=6378 \mathrm{~km},\) and \(r_{c}=3486 \mathrm{~km}\)

See all solutions

Recommended explanations on Geography Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free