Chapter 9: Problem 3
In a particular fresh water sample, the concentrations of cations and anions are (in \(\mu \mathrm{mol} \mathrm{L}^{-1}\) ): \(\begin{array}{lrlr}\mathrm{Na}^{+} & 33 & \mathrm{Cl} & 120 \\\ \mathrm{~K}^{+} & 4 & \mathrm{NO}_{3}^{-} & 13 \\ \mathrm{Mg}^{2+} & 31 & \mathrm{HCO}_{3}^{-} & 270 \\ \mathrm{Ca}^{2+} & 160 & \mathrm{CO}_{3}^{2} & 0.67 \\ & & \mathrm{SO}_{4}^{2-} & 11\end{array}\) Compare the concentration of total positive and negative charge in the solution. Assume that the difference is due to hydronium or hydroxyl ion, and calculate the \(\mathrm{pH}\).
Short Answer
Step by step solution
Calculate Total Positive Charge
Calculate Total Negative Charge
Calculate Charge Difference
Calculate pH of the Solution
Final Step: Conclusion
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