Chapter 13: Problem 34
One way to look at solar payback time time is to note that an installed system will cost something like \(\$ 3,000\) for each \(\mathrm{kW}_{\mathrm{p}}\) (peak capacity), and that you'll produce \(x \mathrm{kWh}\) from that \(1 \mathrm{~kW}_{\mathrm{p}}\) array if your region gets \(x\) hours of full-sun- equivalent on average. Since each kWh of electricity costs something like \(\$ 0.15\), it becomes straightforward to compute the value per day as \(\$ 0.15 x\), and determine how long to match the \$3k investment. The result is independent of the actual array size, depending only on the cost per \(W_{p}\), the solar yield at your location, and the cost of electricity. What would the payback time be, in years, if the cost is \(\$ 3 / W_{p}, 17\) the yield is 6 hours per day of full-sun-equivalent, and electricity in your region costs \(\$ 0.15 / \mathrm{kWh}\) ?
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.