Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Determine if the following electromagnetic waves are linearly polarized, right circularly polarized, left circularly polarized, right élliptically polarized, or left elliptically polarized. All of these waves travel in the \(\hat{a}_{z}\) direction, and \(\omega\) is a constants. (This is a modified version of \(\mathrm{P} 3.34\) from [11].) (a) \(\vec{E}=10 \cos (\omega t-8 z) \hat{a}_{x}+10 \sin (\omega t-8 z) \hat{a}_{y}\) (b) \(\vec{E}=10 \cos \left(\omega t-8 z+\frac{\pi}{4}\right) \hat{a}_{x}+10 \cos \left(\omega t-8 z+\frac{\pi}{4}\right) \hat{a}_{y}\) (c) \(\vec{E}=10 \cos (\omega t-8 z) \hat{a}_{x}-20 \sin (\omega t-8 z) \hat{a}_{y}\) (d) \(\vec{E}=10 \cos (\omega t-8 z) \hat{a}_{x}-10 \sin (\omega t-8 z) \hat{a}_{y}\)

Short Answer

Expert verified
(a) Right circularly polarized; (b) Linearly polarized; (c) Left elliptically polarized; (d) Left circularly polarized.

Step by step solution

01

Identify Polarization for Wave (a)

The electric field given by \( \vec{E}=10 \cos (\omega t-8 z) \hat{a}_{x}+10 \sin (\omega t-8 z) \hat{a}_{y} \) is a combination of cosine and sine terms with equal magnitudes and a phase difference of \( \frac{\pi}{2} \). This matches the characteristic of a right circularly polarized wave, as the electric field rotates in a circular manner in the xy-plane.
02

Identify Polarization for Wave (b)

The electric field given by \( \vec{E}=10 \cos \left(\omega t-8 z+\frac{\pi}{4}\right) \hat{a}_{x}+10 \cos \left(\omega t-8 z+\frac{\pi}{4}\right) \hat{a}_{y} \) has equal magnitudes of the cosine components for both axes. This indicates linear polarization, as the fields do not form a rotating vector and the phase shift is zero between the components.
03

Identify Polarization for Wave (c)

For \( \vec{E}=10 \cos (\omega t-8 z) \hat{a}_{x}-20 \sin (\omega t-8 z) \hat{a}_{y} \), the magnitudes of the components are different, with a relative phase of \( \frac{\pi}{2} \). This results in an ellipse where rotation is determined by the sign and relative magnitude of each term. Here, it indicates left elliptically polarized light due to the sign on the sine term.
04

Identify Polarization for Wave (d)

The electric field \( \vec{E}=10 \cos (\omega t-8 z) \hat{a}_{x}-10 \sin (\omega t-8 z) \hat{a}_{y} \) also has equal magnitudes but with an opposite sign for the sine term compared to wave (a). This configuration matches left circular polarization, as the electric field rotates oppositely in the xy-plane compared to a right circularly polarized wave.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Polarization
Linear polarization is a simple yet crucial concept in the study of electromagnetic waves. It refers to the alignment of the electric field vector along a single direction. In other words, the electric field oscillates in a straight line. The orientation of this line determines the direction of polarization.

Linear polarization can be achieved naturally or through specific filters known as polarizers. In wave (b) of our exercise, \( \vec{E}=10 \cos \left(\omega t-8 z+\frac{\pi}{4}\right) \hat{a}_{x}+10 \cos \left(\omega t-8 z+\frac{\pi}{4}\right) \hat{a}_{y} \),we see equal magnitudes in the cosine components. The lack of a phase difference means no rotation occurs around the axis. Thus, this is a classic case of a linearly polarized wave.
  • Linear polarization is often used in technologies such as sunglasses and camera lenses to reduce glare.
  • To achieve linear polarization, waves can pass through specialized crystals that only allow electric fields in a particular direction.
Circular Polarization
Circular polarization occurs when the electric field vector of an electromagnetic wave rotates in a circular motion at a constant rate as it propagates. This can be viewed in two variations: right circular polarization and left circular polarization.

In wave (a), \( \vec{E}=10 \cos (\omega t-8 z) \hat{a}_{x}+10 \sin (\omega t-8 z) \hat{a}_{y} \), the equal magnitudes of sine and cosine components along with a \( \frac{\pi}{2} \) phase difference results in right circular polarization. Conversely, wave (d), \( \vec{E}=10 \cos (\omega t-8 z) \hat{a}_{x}-10 \sin (\omega t-8 z) \hat{a}_{y} \), has similar characteristics but with an opposite sign on the sine term, indicating left circular polarization.
  • Circular polarization is used in satellite communications and 3D movie glasses to help distinguish signals or images that would otherwise interfere with each other.
  • Understanding the basics of circular polarization is essential for working with antennae and other communication devices.
  • It is interesting to note that circular polarization can reduce signal degradation caused by reflections.
Elliptical Polarization
Elliptical polarization is a more general form of polarization that encompasses both linear and circular polarizations. It is characterized by the electric field vector tracing out an ellipse in the plane perpendicular to the direction of wave propagation.

Wave (c) in our exercise, \( \vec{E}=10 \cos (\omega t-8 z) \hat{a}_{x}-20 \sin (\omega t-8 z) \hat{a}_{y} \), exhibits elliptical polarization. Here, the unequal magnitudes of the cosine and sine components cause the electric field to trace an elliptical path, with the negative sign on the sine term indicating a left-handed rotation.
  • Elliptical polarization is often encountered in real-world scenarios as perfectly linear or circular polarization is rare.
  • It provides advantages in certain optical systems, particularly where beam shaping is crucial.
  • Through the use of quarter-wave plates and other devices, elliptical polarization can be converted into linear or circular polarization.
Electromagnetic Waves Analysis
Electromagnetic waves are a cornerstone of modern communication and technology. Analyzing these waves is crucial for understanding phenomena and designing systems that use electromagnetic properties efficiently.

The analysis involves evaluating the components, magnitudes, and phases of electric and magnetic fields, as these determine the wave's behavior and polarization. From our exercise, each example wave illustrates different polarization characteristics resulting from variations in these properties.
  • Electromagnetic wave analysis helps in designing devices like antennas and sensors where precise control of wave polarization improves performance.
  • The principles learned through analyzing electromagnetic waves find applications in areas from medical imaging to radio broadcasting.
  • Using mathematical tools and simulation software can aid in visualizing and manipulating electromagnetic wave properties for various engineering projects.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An antenna is designed to operate between \(4.98 \mathrm{GHz}\) and \(5.02 \mathrm{GHz}\) for a bandwidth of \(\Delta f=0.04 \mathrm{GHz}\). Find \(\Delta \lambda,\) the wavelength range over which the antenna is designed to operate. Hint: The answer is NOT \(7.5 \mathrm{~m}\).

Some speculate that alien civilizations might be able to watch TV programs that escape the earth's atmosphere. To get an idea of the likelihood for this to occur, consider an isotropic antenna in outer space transmitting a \(200 \mathrm{MHz}\) TV signal. Assume that the alien civilization uses an antenna with surface area \(0.5 \mathrm{~m}^{2}\) and has the technology to detect a signal with power as low as \(5 \cdot 10^{-22} \mathrm{~W}\). What is the minimum power that must be transmitted for detection to occur at a distance of 1.0 light year?

Project ELF, described in Sec. 4.4.1, was an extremely low frequency, \(76 \mathrm{~Hz},\) radio system set by the military to communicate with submarines. It had facilities near Clam Lake, Wisconsin and Republic, Michigan, 148 miles apart [52]. Because these facilities were located a fraction of a wavelength apart, antennas at these locations acted as part of a single array. The length of all antenna elements was 84 miles [52]. Assume it took 18 minutes to transmit a three letters message using 8 bit ASCII, and assume signals travel close to the speed of light in free space. (a) Calculate the ratio of the distance between the transmitting facilities to the wavelength. (b) Calculate the ratio of the length of all antenna elements to the wavelength. (c) What was the speed of communication in bits per second? (d) How many wavelengths long were each bit?

See all solutions

Recommended explanations on Environmental Science Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free