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A particular piezoelectric device has a cross sectional area of \(10^{-5} \mathrm{~m}^{2}\). When a stress of \(800 \frac{\mathrm{N}}{\mathrm{m}^{2}}\) is applied, the device compresses by \(10 \mu \mathrm{m}\). Under these conditions, the device can generate \(2.4 \cdot 10^{-9} \mathrm{~J} .\) Calculate the efficiency of the device.

Short Answer

Expert verified
The efficiency of the device is 3%.

Step by step solution

01

Calculate the Work Done on the Device by the Stress

Work done is determined by the formula \( W = F \cdot d \), where \( F \) is the force applied and \( d \) is the displacement. First, calculate the force \( F \) using the stress \( \sigma = \frac{F}{A} \). From here, \( F = \sigma \cdot A = 800 \frac{\mathrm{N}}{\mathrm{m}^2} \times 10^{-5} \mathrm{~m}^2 = 8 \times 10^{-3} \mathrm{~N} \). Then calculate \( W = F \cdot d = 8 \times 10^{-3} \mathrm{~N} \cdot 10 \times 10^{-6} \mathrm{~m} = 8 \times 10^{-8} \mathrm{~J} \).
02

Calculate the Efficiency of the Device

Efficiency is given by \( \eta = \frac{E_{out}}{E_{in}} \times 100\% \), where \( E_{out} \) is the energy generated and \( E_{in} \) is the work done. Substituting the known values \( E_{out} = 2.4 \times 10^{-9} \mathrm{~J} \) and \( E_{in} = 8 \times 10^{-8} \mathrm{~J} \), calculate \( \eta = \frac{2.4 \times 10^{-9} \mathrm{~J}}{8 \times 10^{-8} \mathrm{~J}} \times 100\% = 3\% \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Efficiency Calculation
The efficiency of a piezoelectric device is a measure of how well it converts input energy into output energy. This metric is crucial for evaluating the performance of the device. To calculate efficiency, use the formula:
  • \( \eta = \frac{E_{out}}{E_{in}} \times 100\% \)
Here:
  • \( E_{out} \) is the energy generated by the device, which is the useful output.
  • \( E_{in} \) is the energy input into the system, calculated as the work done on the device during operation.
In our case:
  • \( E_{out} = 2.4 \times 10^{-9} \mathrm{~J} \)
  • \( E_{in} = 8 \times 10^{-8} \mathrm{~J} \)
Substitute these values into the efficiency formula to find:
  • \( \eta = \frac{2.4 \times 10^{-9}}{8 \times 10^{-8}} \times 100\% = 3\% \)
This means the device is converting 3% of the input energy into useful output energy, which is typical for piezoelectric devices. Despite the low efficiency, they are preferred for their reliability and their ability to convert mechanical stress directly into electrical energy.
Work and Energy
Understanding work and energy is fundamental in assessing the performance of piezoelectric devices. Work is done when a force causes an object to move in the direction of the force. In the context of piezoelectric devices, work performed on the device involves mechanical stress.The work done on the device is calculated using:
  • \( W = F \cdot d \)
where:
  • \( F \) is the force applied, which can be derived from stress and the device's cross-sectional area.
  • \( d \) is the displacement the device undergoes.
To find work, initially calculate the force using the formula:
  • \( F = \sigma \cdot A \)
Given:
  • \( \sigma = 800 \frac{\mathrm{N}}{\mathrm{m}^{2}} \)
  • \( A = 10^{-5} \mathrm{~m}^{2} \)
The force becomes:
  • \( F = 800 \times 10^{-5} = 8 \times 10^{-3} \mathrm{~N} \)
With a displacement of \( 10 \mu \mathrm{m} \) or \( 10 \times 10^{-6} \mathrm{~m} \), the work done is:
  • \( W = 8 \times 10^{-3} \mathrm{~N} \cdot 10 \times 10^{-6} \mathrm{~m} = 8 \times 10^{-8} \mathrm{~J} \)
This work is the total energy input into the device, an essential component for calculating efficiency.
Stress and Force Calculation
Piezoelectric devices rely on their ability to convert stress into electric energy. Calculating stress and subsequently force is crucial to understanding the energy conversion process.Stress, \( \sigma \), is defined as the force per unit area, and is calculated using:
  • \( \sigma = \frac{F}{A} \)
In this exercise:
  • Stress \( \sigma = 800 \frac{\mathrm{N}}{\mathrm{m}^{2}} \), which serves as the given input condition.
  • The cross-sectional area of the device is \( A = 10^{-5} \mathrm{~m}^{2} \).
Given these, the force \( F \) can be calculated by rearranging the stress formula:
  • \( F = \sigma \times A \)
  • This results in \( F = 800 \times 10^{-5} = 8 \times 10^{-3} \mathrm{~N} \).
This force is the mechanical input acting over the device's area, which when combined with the displacement, allows for the calculation of the work done on the device. Understanding the relationship between stress, force, and area is foundational for mastering piezoelectric device operations.

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Most popular questions from this chapter

According to the data sheet, a piezoelectric device is \(3 \%\) efficient. A coworker says that energy is not conserved in the device because \(97 \%\) of the energy is lost when it is used. Explain what is wrong with your coworker's explanation.

A particular piezoelectric device has a cross sectional area of \(10^{-5} \mathrm{~m}^{2}\) and an efficiency of \(5 \% .\) When a stress of \(1640 \frac{\mathrm{N}}{\mathrm{m}^{2}}\) is applied to the device, it oscillates with an average velocity of \(0.01 \frac{\mathrm{m}}{\mathrm{s}} .\) Calculate the power that can be generated from the device.

A piezoelectric material has permittivity \(\epsilon_{r}=2.5 .\) If the material is placed in an electric field of strength \(|\vec{E}|=2 \cdot 10^{3} \frac{\mathrm{V}}{\mathrm{m}}\) and is subjected to a stress of \(|\vec{\zeta}|=200 \frac{\mathrm{N}}{\mathrm{m}^{2}},\) the material polarization of the material is \(3.2 \cdot 10^{-8} \frac{\mathrm{C}}{\mathrm{m}^{2}} .\) Calculate \(d,\) the piezoelectric strain constant.

A parallel plate capacitor has a capacitance of \(3 \mu \mathrm{F}\). (a) Suppose another capacitor is made using the same dielectric material and with the same cross sectional area. However, the thickness of the dielectric between the plates of the capacitor is double that of the original capacitor. What is its capacitance? (b) Suppose a third capacitor is made with the same cross sectional area and thickness as the first capacitor, but from a material with twice the permittivity. What is its capacitance?

A cylindrical sandwich cookie has a radius of 0.75 in. The cookie is made from two wafers, each of thickness 0.15 in, which are perfect dielectrics of relative permittivity \(\epsilon_{r}=2.8 .\) Between the wafers is a layer of cream filling of thickness 0.1 in which is a perfect dielectric of relative permittivity \(\epsilon_{r}=2.2 .\) Find the overall capacitance of the cookie. Hint: Capacitances in series combine as \(\frac{1}{\frac{1}{C_{1}}+\frac{1}{C_{2}}}\).

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