Question

During a presidential election, a high school held its own mock election. Students had the option to vote for Candidate A, Candidate B, or several other candidates. They could also choose to spoil their ballot. The table below displays a summary of the election results. $$ \begin{array}{|l|c|c|c|c|} & \text { Candidate A } & \text { Candidate B } & \text { Other } & \text { Total } \\ \hline \text { 10th grade } & 0.32 & 0.58 & 0.10 & 1.00 \\ \hline \text { 11th grade } & 0.50 & 0.42 & 0.08 & 1.00 \\ \hline \text { 12th grade } & 0.63 & 0.32 & 0.05 & 1.00 \\ \hline \text { Total } & 0.48 & 0.44 & 0.08 & 1.00 \\ \hline \end{array} $$ 614 students voted for Candidate A. Approximately how many students attend the school?

Short answer

Approximately 1279 students attend the high school.

Step-by-step solution

Identify the percentage of students who voted for Candidate A

From the table, we can see that 48% (0.48) of the total students voted for Candidate A.

Find the total number of students

We know that 614 students voted for Candidate A, and they represent 48% (0.48) of the total students. Let's call the total number of students "x". To find the total number of students (x), we need to set up the equation: \(0.48x = 614\)

Solve the equation

Now, to find the value of "x", we need to divide both sides of the equation by 0.48: \( x = \frac{614}{0.48} \)

Calculate the total number of students

Now, let's calculate the value of "x": \( x \approx \frac{614}{0.48} \approx 1279 \) So, approximately 1279 students attend the high school.