Question

A certain homeowner uses a gas edger to clean up his lawn every time he mows. If the edger uses 160 milliliters of fuel each time, what is the maximum number of times the homeowner can edge his lawn with 8 liters of fuel? \((1\) liter \(=1,000\) milliliters \()\) A) 5 B) 50 C) 100 D) 1,000 $$ \begin{aligned} &\text { Assignment Choice for Two Physics Classes }\\\ &\begin{array}{|l|c|c|c|} \hline & \text { Dr. Soper } & \text { Mr. Coelho } & \text { Total } \\ \hline \text { Lab Report Only } & 17 & 21 & 38 \\ \hline \begin{array}{l} \text { Lab Report and Final } \\ \text { Exam } \end{array} & 3 & 2 & 5 \\ \hline \text { Total } & 20 & 23 & 43 \\ \hline \end{array} \end{aligned} $$

Short answer

The homeowner can use the gas edger a maximum of 50 times with 8 liters of fuel. So, the correct answer is \(B\) 50.

Step-by-step solution

Convert liters of fuel to milliliters

Given that 1 liter equals 1,000 milliliters, we need to convert 8 liters of fuel into milliliters using the conversion factor for liters to milliliters. \[8 \text{ liters} \times \frac{1,000 \text{ milliliters}}{1 \text{ liter}}\]

Calculate the total amount of fuel in milliliters

Now, multiply 8 by 1,000 to find the total amount of fuel in milliliters. \[8 \times 1,000 = 8,000 \text{ milliliters}\] So, the homeowner has 8,000 milliliters of fuel available.

Divide the total fuel by the fuel consumed each time

Since the edger consumes 160 milliliters of fuel each time, to find the maximum number of times the homeowner can use the edger, divide the total fuel by the fuel consumed each time. \[\frac{8,000 \text{ milliliters}}{160 \text{ milliliters/use}}\]

Calculate the maximum number of uses

Divide 8,000 by 160 to find the maximum number of times the homeowner can use the edger before the fuel runs out. \[\frac{8,000}{160} = 50\] So, the homeowner can use the gas edger a maximum of 50 times with 8 liters of fuel. The correct answer is B) 50.