Chapter 9: Problem 1305
At a given temperature the root mean square velocities of Oxygen and hydrogen molecules are in the ratio (A) \(1: 4\) (B) \(1: 16\) (C) \(16: 1\) (D) \(4: 1\)
Short Answer
Expert verified
The root mean square velocities of Oxygen and Hydrogen molecules are in the ratio \(1:4\). The correct answer is (A) \(1:4\).
Step by step solution
01
Write down the formula for root mean square velocity
The root mean square velocity (Vrms) of a gas is given by the formula:
\(V_{rms} = \sqrt{\frac{3RT}{M}}\), where R is the universal gas constant, T is the temperature, and M is the molar mass of the gas.
02
Assign values to the constants and variables
For this exercise, let's assign the following values:
R = 8.314 J/mol∙K (universal gas constant)
T = temperature (constant for both Oxygen and Hydrogen)
M_oxygen = M_o (molar mass of Oxygen) = 32 g/mol
M_hydrogen = M_h (molar mass of Hydrogen) = 2 g/mol
03
Write down the Vrms equations for Oxygen and Hydrogen
Using the formula for root mean square velocity, we can write down the Vrms equations for Oxygen and Hydrogen:
\(V_{rms,oxygen} = \sqrt{\frac{3RT}{M_o}}\)
\(V_{rms,hydrogen} = \sqrt{\frac{3RT}{M_h}}\)
04
Write the velocity ratio
We want to find the ratio of the root mean square velocities of Oxygen and Hydrogen. We can write it as:
\(\frac{V_{rms,oxygen}}{V_{rms,hydrogen}} = \frac{\sqrt{\frac{3RT}{M_o}}}{\sqrt{\frac{3RT}{M_h}}}\)
05
Simplify the velocity ratio
Now, let's simplify the ratio equation and solve for the velocity ratio:
\(\frac{V_{rms,oxygen}}{V_{rms,hydrogen}} = \frac{\sqrt{\frac{3RT}{M_o}}}{\sqrt{\frac{3RT}{M_h}}}
= \sqrt{\frac{M_h}{M_o}}\)
Considering the molar masses of Oxygen and Hydrogen:
\(\frac{V_{rms,oxygen}}{V_{rms,hydrogen}} = \sqrt{\frac{2}{32}} = \sqrt{\frac{1}{16}}\)
06
Calculate the velocity ratio
Now, let's calculate the root mean square velocity ratio:
\(\frac{V_{rms,oxygen}}{V_{rms,hydrogen}} = \sqrt{\frac{1}{16}} = \frac{1}{4}\)
So the correct ratio is \(1 : 4\).
The correct answer is (A) \(1 : 4\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Root Mean Square Velocity
The concept of root mean square velocity (Vrms) is fundamental in understanding the kinetic theory of gases. It provides a way to measure the average speed of gas molecules at a given temperature. To calculate the Vrms, we use the formula: \[ V_{rms} = \sqrt{\frac{3RT}{M}} \] Where:
- \( R \) is the universal gas constant.
- \( T \) is the temperature in Kelvin.
- \( M \) is the molar mass of the gas in kg/mol.
Molar Mass
Molar mass is the weight of one mole of a given substance, usually measured in g/mol. It signifies the mass of the substance's molecules and plays a critical role in various calculations in chemistry.
When discussing gases, molar mass affects the velocity of the molecules significantly.
A molecule with a smaller molar mass will tend to move faster compared to a molecule with a larger molar mass when both are at the same temperature.
For example, in our exercise:
- Oxygen has a molar mass of 32 g/mol.
- Hydrogen has a molar mass of 2 g/mol.
Universal Gas Constant
The universal gas constant \( R \) is a key component in the ideal gas law and in equations relating to the behavior of gases. It makes the connection between energy and temperature possible, playing an essential part in the root mean square velocity formula. The value of the universal gas constant is commonly used in calculations involving the behavior of ideal gases. Its value is approximately:
- \( R = 8.314 \) J/mol·K