Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

At Which temperature the density of water is maximum? (A) \(4^{\circ} \mathrm{F}\) (B) \(42^{\circ} \mathrm{F}\) (C) \(32^{\circ} \mathrm{F}\) (D) \(39.2^{\circ} \mathrm{F}\)

Short Answer

Expert verified
The density of water is maximum at \(39.2^{\circ} \mathrm{F}\).

Step by step solution

01

Fact Recall

The density of water is known to be at its maximum at a temperature of \(4^{\circ} \mathrm{C}\) (degrees Celsius). However, the given options are in degrees Fahrenheit. Hence, we need to convert this temperature from Celsius to Fahrenheit.
02

Temperature Conversion Formula

To convert the temperature from Celsius to Fahrenheit, we can use the following formula: \[F = \frac{9}{5} \times C + 32\] Here, F denotes the temperature in Fahrenheit, and C denotes the temperature in Celsius.
03

Convert Temperature to Fahrenheit

We need to convert \(4^{\circ} \mathrm{C}\) to Fahrenheit. Plugging the value into the formula, we get: \[F = \frac{9}{5} \times 4 + 32\]
04

Calculate the Temperature

To find the answer, we need to perform the calculations. \begin{align*} F &= \frac{9}{5} \times 4 + 32 \\ &= \frac{9 \times 4}{5} + 32 \\ &= \frac{36}{5} + 32 \\ & = 7.2 + 32 \\ & = 39.2 \end{align*} Hence, the density of water is maximum at \(39.2^{\circ} \mathrm{F}\) which corresponds to (D) as our correct answer.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An ideal refrigerator has a freezer at a temperature of \(-13\) C, The coefficient of performance of the engine is 5 . The temperature of the air to which heat is rejected will be. (A) \(325^{\circ} \mathrm{C}\) (B) \(39^{\circ} \mathrm{C}\) (C) \(325 \mathrm{~K}\) (D) \(320^{\circ} \mathrm{C}\)

Instructions:Read the assertion and reason carefully to mask the correct option out of the options given below. (A) If both assertion and reason are true and the reason is the correct explanation of the assertion. (B) If both assertion and reason are true but reason is not be correct explanation of assertion. (C) If assertion is true but reason is false. (D) If the assertion and reason both are false. Assertion: The carnot is useful in understanding the performance of heat engine Reason: The carnot cycle provides a way of determining the maximum possible efficiency achievable with reservoirs of given temperatures. (A) \(\mathrm{A}\) (B) B (C) \(\mathrm{C}\) (D) \(\mathrm{D}\)

A gas expands \(0.25 \mathrm{~m}^{3}\) at Constant Pressure \(10^{3}\left(\mathrm{~N} / \mathrm{m}^{2}\right)\) the work done is (A) \(250 \mathrm{~J}\) (B) \(2.5\) erg (C) \(250 \mathrm{~W}\) (D) \(250 \mathrm{~N}\)

One mole of an ideal gas $\left(\mathrm{C}_{\mathrm{p}} / \mathrm{C}_{\mathrm{v}}\right)=\gamma$ at absolute temperature \(\mathrm{T}_{1}\) is adiabatically compressed from an initial pressure \(\mathrm{P}_{1}\) to a final pressure \(\mathrm{P}_{2}\) The resulting temperature \(\mathrm{T}_{2}\) of the gas is given by. (A) $\mathrm{T}_{2}=\mathrm{T}_{1}\left\\{\mathrm{p}_{2} / \mathrm{p}_{1}\right\\}^{\\{\gamma /(\gamma-1)\\}}$ (B) $\mathrm{T}_{2}=\mathrm{T}_{1}\left\\{\mathrm{p}_{2} / \mathrm{p}_{1}\right\\}^{\\{(\gamma-1) / \gamma\\}}$ (C) $\mathrm{T}_{2}=\mathrm{T}_{1}\left\\{\mathrm{p}_{2} / \mathrm{p}_{1}\right\\}^{\gamma}$ (D) $\mathrm{T}_{2}=\mathrm{T}_{1}\left(\mathrm{p}_{2} / \mathrm{p}_{1}\right)^{\gamma-1}$

An ideal gas heat engine is operating between \(227^{\circ} \mathrm{C}\) and \(127^{\circ} \mathrm{C}\). It absorbs \(10^{4} \mathrm{~J}\) Of heat at the higher temperature. The amount of heat Converted into. work is \(\ldots \ldots\) J. (A)2000 (B) 4000 (C) 5600 (D) 8000

See all solutions

Recommended explanations on English Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free