Question

What is the value of absolute temperature on the Celsius Scale? (A) \(-273.15^{\circ} \mathrm{C}\) (B) \(100^{\circ} \mathrm{C}\) (C) \(-32^{\circ} \mathrm{C}\) (D) \(0^{\circ} \mathrm{C}\)

Short answer

The value of absolute temperature on the Celsius Scale is \(-273.15 ^{\circ} \mathrm{C}\).

Step-by-step solution

Relationship between Celsius and Kelvin scales

The relationship between the Celsius (°C) and Kelvin (K) temperature scales is given by the following formula: \(T_{K} = T_{°C} + 273.15\) Where \(T_{K}\) is the temperature in Kelvin and \(T_{°C}\) is the temperature in Celsius.

Define absolute zero

Absolute zero is the lowest possible temperature where atoms would stop moving. This temperature is defined as \(0 \, K\). We need to find the equivalent temperature in Celsius to find the absolute temperature on the Celsius Scale.

Calculate the equivalent temperature in Celsius

Using the relationship between Celsius and Kelvin, we plug in the value for absolute zero on the Kelvin scale and solve for Celsius: \(0 \, K = T_{°C} + 273.15\) Now, solve for \(T_{°C}\): \(T_{°C} = 0 \, K - 273.15\) \(T_{°C} = -273.15 ^{\circ} \mathrm{C}\)

Choose the correct answer

The value of absolute zero on the Celsius Scale is \(-273.15 ^{\circ} \mathrm{C}\). Hence, the correct answer is: (A) \(-273.15^{\circ} \mathrm{C}\)