Question

The angular momentum of a wheel changes from \(2 \mathrm{~L}\) to $5 \mathrm{~L}$ in 3 seconds what is the magnitudes of torque acting on it? \(\\{\mathrm{A}\\} \mathrm{L}\) \(\\{\mathrm{B}\\} \mathrm{L} / 2\) \(\\{\mathrm{C}\\} \mathrm{L} / 3\) \(\\{\mathrm{D}\\} \mathrm{L} / 5\)

Short answer

The correct answer is: \(\boxed{\mathrm{(A)}\, \mathrm{L}}\).

Step-by-step solution

Determine the Change in Angular Momentum

To find the change in angular momentum, we will subtract the initial angular momentum from the final angular momentum: ΔL = L_final - L_initial = 5L - 2L = 3L

Calculate Torque

Now that we have the change in angular momentum, we can use the formula for torque to find the magnitude of the torque acting on the wheel: Torque = ΔL / Δt = 3L / 3s = L The magnitude of the torque acting on the wheel is L. The correct answer is: \(\boxed{\mathrm{(A)}\, \mathrm{L}}\).