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Two discs of the same material and thickness have radii \(0.2 \mathrm{~m}\) and \(0.6 \mathrm{~m}\) their moment of inertia about their axes will be in the ratio \(\\{\mathrm{A}\\} 1: 81\) \(\\{\mathrm{B}\\} 1: 27\) \(\\{C\\} 1: 9\) \(\\{\mathrm{D}\\} 1: 3\)

Short Answer

Expert verified
The ratio of the moments of inertia for the two discs is 1:81. Since both discs have the same material and thickness, their masses are proportional to the square of their radii. Using the formula for the moment of inertia of a disc (\(I = \frac{1}{2}mr^2\)), we calculate the moments of inertia for both discs and determine the ratio \(\frac{I_1}{I_2} = \frac{1}{81}\). The correct answer is \(\mathrm{A} \: 1: 81\).

Step by step solution

01

Formula for the moment of inertia of a disc

Recall the formula for the moment of inertia (I) of a solid disc about its central axis: \[I = \frac{1}{2}mr^2\] where m is the mass and r is the radius of the disc.
02

Calculate the moments of inertia for both discs

Since both discs have the same material and thickness, their masses will be proportional to the square of their radii, i.e., \(m_2 = k(0.2)^2\) and \(m_1 = k(0.6)^2\) , where k is a constant of proportionality. Now we can calculate the moments of inertia for both discs using the given radii and the proportional masses: \(I_1 = \frac{1}{2}(k(0.2)^2)(0.2)^2 = \frac{k}{50}\) \(I_2 = \frac{1}{2}(k(0.6)^2)(0.6)^2 = \frac{9k}{10}\)
03

Calculate the ratio of the moments of inertia

We are interested in finding the ratio \(\frac{I_1}{I_2}\). Using the values we found in the previous step, we can write: \[\frac{I_1}{I_2} = \frac{\frac{k}{50}}{\frac{9k}{10}} = \frac{1}{81}\]
04

Find the matching option

The ratio we obtained is 1:81, which matches option A. Therefore, the correct answer is: \(\boxed{\mathrm{A}\: 1: 81}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solid Disc
A solid disc is a three-dimensional circular object, typically flat, with uniform thickness and density. This means that the material composition is consistent throughout the disc, making it an idealized object for various physics calculations. Discs are foundational in rotational mechanics, particularly in understanding concepts like angular velocity and moment of inertia.
When considering a solid disc in physics, the key assumption is that the entire mass of the disc is distributed evenly across its surface. This uniform mass distribution is crucial for simplifying calculations. In practical terms, when you spin a solid disc, each point on the disc experiences the same centripetal force, which makes predictive calculations feasible using mathematical formulas like those relating to moment of inertia.
Central Axis
The central axis of a disc refers to an imaginary line that runs perpendicular to the disc's plane and passes through its center. Think of this axis as the point around which the disc spins or rotates.
The central axis is an essential concept in calculating the moment of inertia because it determines the balance and symmetry of the disc during rotation. For a solid disc, the moment of inertia calculation assumes rotation about this central axis, as it's the simplest case and provides symmetry, making calculations accurate and manageable.
The central axis affects the rotational dynamics such as torque and angular acceleration. Understanding this axis is key to grasping phenomena like gyroscopic motion, which relies on the disc maintaining its orientation due to its rotational inertia.
Proportional Mass
In the problem of calculating the moment of inertia for two discs of differing radii, the concept of proportional mass plays a fundamental role. Since both discs have the same thickness and are made from the same material, the mass of each disc is proportional to the square of its radius.
This is derived from the fact that, for a disc, mass is related to the area it covers. The formula for area is \(\pi r^2\), meaning that mass grows with the square of the radius, assuming constant density and thickness. In the exercise, the assumption is used that the mass of each disc can be expressed as \(m = k imes r^2\), where k is a constant.
  • This means if one disc has a radius that is three times as long as another disc, its mass will be nine times greater.
  • This principle of proportionality is key in solving for the moment of inertia by allowing us to express mass in relation to the radius and another proportionality factor.
Radius of Disc
The radius of a disc is the distance from its center to any point on the edge. It is a fundamental property that not only helps define the shape and size of the disc but also its rotational characteristics.
In calculations involving a disc's moment of inertia, the radius is crucial because it helps determine how much mass is distributed about the central axis. The formula for the moment of inertia of a solid disc is \[I = \frac{1}{2}mr^2\] ,
reflecting that the moment of inertia depends heavily on the square of the radius. This specific relationship highlights how quickly the moment of inertia increases as the disc’s size increases, due to the distribution of mass further from the central axis.
When analyzing two discs, as in the exercise, noting the disparity in radii helps understand why they have different moments of inertia, with a smaller radius corresponding to a smaller moment of inertia. This directly influences the rotational behavior of each disc, which is foundational in mechanical design and analysis.

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Most popular questions from this chapter

A circular disc of radius \(\mathrm{R}\) is removed from a bigger disc of radius \(2 \mathrm{R}\). such that the circumferences of the disc coincide. The centre of mass of the remaining portion is \(\alpha R\) from the centre of mass of the bigger disc. The value of \(\alpha\) is. \(\\{\mathrm{A}\\} 1 / 2\) \\{B \\} \(1 / 6\) \\{C\\} \(1 / 4\) \(\\{\mathrm{D}\\}[(-1) / 3]\)

Statement \(-1\) - Two cylinder one hollow and other solid (wood) with the same mass and identical dimensions are simultaneously allowed to roll without slipping down an inclined plane from the same height. The hollow will reach the bottom of inclined plane first. Statement \(-2-\mathrm{By}\) the principle of conservation of energy, the total kinetic energies of both the cylinders are identical when they reach the bottom of the incline. \(\\{\mathrm{A}\\}\) Statement \(-1\) is correct (true), Statement \(-2\) is true and Statement- 2 is correct explanation for Statement \(-1\) \\{B \\} Statement \(-1\) is true, statement \(-2\) is true but statement- 2 is not the correct explanation four statement \(-1\). \\{C\\} Statement - 1 is true, statement- 2 is false \\{D \(\\}\) Statement- 2 is false, statement \(-2\) is true

A straight rod of length \(L\) has one of its ends at the origin and the other end at \(\mathrm{x}=\mathrm{L}\) If the mass per unit length of rod is given by Ax where \(A\) is constant where is its centre of mass. \(\\{\mathrm{A}\\} \mathrm{L} / 3\) \(\\{\mathrm{B}\\} \mathrm{L} / 2\) \(\\{\mathrm{C}\\} 2 \mathrm{~L} / 3\) \(\\{\mathrm{D}\\} 3 \mathrm{~L} / 4\)

Statement \(-1-\) A thin uniform rod \(A B\) of mass \(M\) and length \(\mathrm{L}\) is hinged at one end \(\mathrm{A}\) to the horizontal floor initially it stands vertically. It is allowed to fall freely on the floor in the vertical plane, The angular velocity of the rod when its ends \(B\) strikes the floor \(\sqrt{(3 g / L)}\) Statement \(-2\) - The angular momentum of the rod about the hinge remains constant throughout its fall to the floor. \(\\{\mathrm{A}\\}\) Statement \(-1\) is correct (true), Statement \(-2\) is true and Statement- 2 is correct explanation for Statement - 1 \\{B \\} Statement \(-1\) is true, statement \(-2\) is true but statement- 2 is not the correct explanation four statement \(-1\). \\{C\\} Statement \(-1\) is true, statement- 2 is false \\{D \(\\}\) Statement- 2 is false, statement \(-2\) is true

The centre of mass of a systems of two particles is (A) on the line joining them and midway between them (B) on the line joining them at a point whose distance from each particle is proportional to the square of the mass of that particle. (C) on the line joining them at a point whose distance from each particle inversely proportional to the mass of that particle. (D) On the line joining them at a point whose distance from each particle is proportional to the mass of that particle.

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