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The electrical resistance of depletion layer is large because (A) it contains electrons as charge carriers (B) it has holes as charge carriers. (C) it has no charge carriers. (D) It has large number of charge carriers

Short Answer

Expert verified
The correct reason for the large electrical resistance in the depletion layer is option (C) because it has no charge carriers.

Step by step solution

01

Analyze the first option

Option (A) states that the electrical resistance of the depletion layer is large because it contains electrons as charge carriers. This is not the correct reason because the presence of electrons as charge carriers would actually lead to electrical conduction, not an increase in resistance.
02

Analyze the second option

Option (B) states that the electrical resistance of the depletion layer is large because it has holes as charge carriers. This is also not the correct reason because, like electrons, the presence of holes as charge carriers would also lead to electrical conduction, not an increase in resistance.
03

Analyze the third option

Option (C) states that the electrical resistance of the depletion layer is large because it has no charge carriers. This is the correct reason because, in the depletion layer, the recombination of electrons and holes leaves behind a region with no charge carriers, thus resulting in a large electrical resistance.
04

Analyze the fourth option

Option (D) states that the electrical resistance of the depletion layer is large because it has a large number of charge carriers. This is not the correct reason because having a large number of charge carriers would lead to an increase in electrical conduction, not an increase in resistance.
05

Conclusion

Based on the analysis of each option, the correct reason for the large electrical resistance in the depletion layer is option (C) because it has no charge carriers.

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Most popular questions from this chapter

In a P-N junction, there is no appreciable current if (A) a potential difference is applied across the junction (B) it is impossible (C) P-section is a made positive and N-section negative (D) a potential difference is applied across junction making P section negative and N-section positive.

A P-N junction is said to be forward based when (A) a magnetic field is applied in the region of junction. (B) a potential difference is applied across \(\mathrm{P}\) and \(\mathrm{N}\) regions making \(\mathrm{P}\) region negative and \(\mathrm{N}\) region positive. (C) not potential difference is applied across \(\mathrm{P}\) and \(\mathrm{N}\) regions. (D) a potential difference is applied across \(\mathrm{P}\) and \(\mathrm{N}\) regions making P region positive and N region negative.

In a semiconductor diode, barrier potential offers opposition to only (A) free electrons in \(\mathrm{N}\) region (B) holes in the P region (C) minority carriers in both regions (D) majority carriers in both regions.

When a P-N junction diode is reverse biased (A) height of the potential barriers decreases (B) no change in the current takes place (C) electrons and holes move away from the junction deflection region. (D) electrons and holes one attracted towards each other and move towards the deflection region.

When \(\mathrm{P}-\mathrm{N}\) junction diode is forward based, then (A) Both the depletion region and barrier height are reduced. (B) Both depletion region and barrier height are increased. (C) The deflection region is winded and barrier height is reduced. (D) The depletion region is reduced and barrier height is increased.

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