Chapter 36: Problem 2895
The minimum angle of deviation of a prism of refractive index \(1.732\) is equal to its refracting angle. What is the angle of prism ? (A) \(45^{\circ}\) (B) \(30^{\circ}\) (C) \(60^{\circ}\) (D) \(40^{\circ}\)
Short Answer
Expert verified
The angle of the prism is \(A = 30^{\circ}\).
Step by step solution
01
Understand the Prism Formula
We will be using the Prism Formula to solve this problem, which relates the angle of the prism (A), the angle of minimum deviation (δ), and the refractive index (n) of the prism material.
The Prism Formula is given as follows:
\(n = \frac{\sin{(A + δ)/2}}{\sin{(A/2)}}\)
Since the minimum angle of deviation (δ) is equal to the refracting angle (A), we have:
\(n = \frac{\sin{(A + A)/2}}{\sin{(A/2)}}\)
02
Plug in the given refractive index
Now, we can plug in the given refractive index (1.732) in the Prism Formula and solve for the angle A.
\(1.732 = \frac{\sin{(2A)/2}}{\sin{(A/2)}}\)
03
Simplify and solve for the angle
We now have an equation we can solve for the angle A:
\(1.732 = \frac{\sin{A}}{\sin{(A/2)}}\)
Let's multiply both sides by \(\sin{(A/2)}\) to isolate the sinus of A:
\(1.732 \cdot \sin{(A/2)} = \sin{A}\)
Now we can look for an angle A that satisfies this equation.
04
Check the given options
We will check each option to see which one satisfies the equation.
(A) \(A = 45^{\circ}\)
\(1.732 \cdot \sin{(45/2)} \approx 1.22\)
(B) \(A = 30^{\circ}\)
\(1.732 \cdot \sin{(30/2)} = 1.732\)
Since option B satisfies the equation, the correct answer is:
\(A = 30^{\circ}\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Prism Formula
The prism formula is essential to understanding how light behaves when it passes through a prism. This formula is used to determine the relationship between the angle of the prism, the angle of minimum deviation, and the refractive index of the prism's material. The formula is expressed as: \[ n = \frac{\sin{((A + \delta)/2)}}{\sin{(A/2)}} \] where \( n \) is the refractive index, \( A \) is the angle of the prism, and \( \delta \) is the angle of minimum deviation.
- The sine function \( \sin \) is used due to the nature of light refraction, which causes changes in speed and direction.
- This formula helps to calculate complex relationships in optical experiments, demonstrating the interaction of light with prisms.
Refractive Index
The refractive index of a material defines how much light is bent, or refracted, when it enters the material. It is a critical factor in optics, as it affects how efficiently light propagates through different mediums. The refractive index \( n \) is calculated as the ratio of the speed of light in a vacuum to the speed of light in the material: \[ n = \frac{c}{v} \] where \( c \) is the speed of light in a vacuum, and \( v \) is the speed of light in the material.
- A refractive index greater than 1 indicates that light travels slower in that medium than in a vacuum.
- Materials with a higher refractive index bend light more than those with a lower refractive index.
Angle of Minimum Deviation
The angle of minimum deviation (\( \delta \)) is a key concept in optics. It refers to the smallest angle through which light is deviated as it passes through a prism. This angle occurs when the light travels symmetrically through the prism, meaning the light beam enters and exits the prism at equal angles relative to the prism's faces.
- At the angle of minimum deviation, the path of light inside the prism is parallel to the base.
- This condition often simplifies calculations in optical problems since it relates directly to the prism's refracting angle.