Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

What is the relation between figure of merit \((\mathrm{k})\) and current sensitivity \(\left(\mathrm{S}_{1}\right) ?\) (A) \(\mathrm{S}_{1}=\mathrm{k}^{-1}\) (B) \(\mathrm{S}_{1}=(\mathrm{k} / 2)\) (C) \(\mathrm{S}_{1}=\mathrm{kV}\) (D) \(\mathrm{S}_{1}=(\mathrm{k}) \mathrm{I}\)

Short Answer

Expert verified
(A) \(S1=k^{-1}\)

Step by step solution

01

Understand Figure of Merit (k)

The figure of merit (k) is a dimensionless quantity that shows the performance of a measuring instrument such as a galvanometer. The figure of merit represents the inverse of the amount of magnetic field required for a measuring instrument to deflect per unit current.
02

Understand Current Sensitivity (S1)

Current sensitivity (S1) refers to the deflection produced in an instrument when a unit current flows through it. Essentially, it tells us how sensitive an instrument is to the change in current.
03

Find the Relationship between k and S1

Since the figure of merit (k) represents the inverse of the amount of magnetic field required for an instrument to deflect per unit current, and current sensitivity (S1) represents the deflection produced in an instrument when a unit current flows through it, we can say that: \(S1 = k^{-1}\) Therefore, the correct answer is: (A) \(S1=k^{-1}\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An ammeter of range \(5 \mathrm{~A}\) is to be converted into an voltmer of range \(10 \mathrm{~V}\). If the resistance of ammeter be \(0.1\), then what resistance should be connected in series with it ? (A) \(4.9 \Omega\) (B) \(2.1 \Omega\) (C) \(1.1 \Omega\) (D) \(1.9 \Omega\)

A moving coil galvanometer has 150 equal divisions, Its current sensitivity is 10 divisions per milli-ampere and voltage sensitivity is 2 divisions per milli-volt. In order that each divisions reads \(1 \mathrm{~V}\), What will be the resistance in ohms needed to be connected in series with the coil? (A) \(10^{3}\) (B) 99995 (C) 9995 (D) \(10^{5}\)

The range of a galvanometer of resistance \(\mathrm{G}\) ohm is \(\mathrm{V}\) volt. The resistance required to be connected in series with it in order to convert it into voltmeter of range \(\mathrm{nV}\) volt will be (A) (G/n) (B) \(\mathrm{nG}\) (C) \((\mathrm{n}-1) \mathrm{G}\) (D) \([\mathrm{G} /(\mathrm{n}-1)]\)

The seave of a galvanometer of resistance \(100 \mathrm{Q}\) contains 25 divisions. It gives a deflection of 1 division on passing a current of $4 \times 10^{-4} \mathrm{~A}$. The resistance in ohm to be added to it. so that it may become a voltmeter of range \(2.5 \mathrm{~V}\) is (A) 250 (B) 300 (C) 150 (D) 100

A galvanometer with resistance \(100 \Omega\) is converted into an ammeter with a resistance of \(0.1\). The galvanometer shows full scale deflection with current of \(100 \mu \mathrm{A}\). Then what will be the minimum current in the circuit for full scale deflection of galvanometer ? (A) \(0.1001 \mathrm{~mA}\) (B) \(100.1 \mathrm{~mA}\) (C) \(1000.1 \mathrm{~mA}\) (D) \(1.001 \mathrm{~mA}\)

See all solutions

Recommended explanations on English Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free