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Chapter 3: Problem 379

A lift of mass \(1000 \mathrm{~kg}\) is moving with an acceleration of $1 \mathrm{~ms}^{-2}$ in upward direction Tension developed in the rope of lift is \(\mathrm{N}\left(\mathrm{g}=9.8 \mathrm{~ms}^{-2}\right)\) (A) 9800 (B) 10,000 (C) 10,800 (D) 11,000

Short Answer

Expert verified
The tension developed in the rope of the lift is \(10,800 N\).

Step by step solution

01

Identify the given values

We are given: - Mass of the lift (m) = 1000 kg - Acceleration due to gravity (g) = 9.8 m/s² - Acceleration in the upward direction (a) = 1 m/s²
02

Use Newton's second law of motion to calculate the tension

We will use Newton's second law of motion to calculate the tension (T) in the rope: Tension (T) = Mass (m) × (g + acceleration) Substitute the given values into the equation: T = 1000 kg × (9.8 m/s² + 1 m/s²)
03

Solve for the tension

Now, solve for the tension: T = 1000 kg × (10.8 m/s²) T = 10,800 N
04

Identify the correct option

From our calculation, we have found that the tension developed in the rope of the lift is 10,800 N. Comparing this value to the given options, we can see that the correct answer is: (C) 10,800

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