Chapter 3: Problem 363
Newton's third law of motion leads to the law of conservation of (A) Angular momentum (B) Energy (C) mass (D) momentum
Chapter 3: Problem 363
Newton's third law of motion leads to the law of conservation of (A) Angular momentum (B) Energy (C) mass (D) momentum
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Get started for freeA bag of sand of mass \(\mathrm{m}\) is suspended by rope. a bullet of mass \((\mathrm{m} / 30)\) is fired at it with a velocity \(\mathrm{V}\) and gets embedded into it. The velocity of the bag finally is (A) \((31 \mathrm{~V} / 30)\) (B) \((30 \mathrm{~V} / 31)\) (C) \((\mathrm{V} / 31)\) (D) \((\mathrm{V} / 30)\)
A body of mass \(0.05 \mathrm{~kg}\) is falling with acceleration $9.4 \mathrm{~ms}^{-2}$. The force exerted by air opposite to motion is \(\mathrm{N}\) \(\left(g=9.8 \mathrm{~ms}^{-2}\right)\) (A) \(0.02\) (B) \(0.20\) (C) \(0.030\) (D) Zero
Two bodies of equal masses revolve in circular orbits of radii \(\mathrm{R}_{1}\) and \(\mathrm{R}_{2}\) with the same period Their centripetal forces are in the ratio. (A) \(\left(\mathrm{R}_{2} / \mathrm{R}_{1}\right)^{2}\) (B) \(\left(\mathrm{r}_{1} / \mathrm{r}_{2}\right)\) (C) \(\left(\mathrm{R}_{1} / \mathrm{R}_{2}\right)^{2}\) (D) \(\left.\sqrt{(}_{1} R_{2}\right)\)
Formula for true force is (A) \(\mathrm{F}=\mathrm{ma}\) (B) \(\mathrm{F}=[\\{\mathrm{d}(\mathrm{mv})\\} / \mathrm{dt}]\) (C) \(\mathrm{F}=\mathrm{m}(\mathrm{dv} / \mathrm{dt})\) (D) \(F=m\left(d^{2} x / d t^{2}\right)\)
The minimum force required to start pushing a body up a rough (coefficient of) inclined plane is \(\mathrm{F}_{1}\). While the minimum force needed to prevent it from sliding down is \(\mathrm{F}_{2}\). If the inclined plane makes an angle \(\theta\) from the horizontal. such that \(\tan \theta=2 \mu\) than the ratio \(\left(\mathrm{F}_{1} / \mathrm{F}_{2}\right)\) is (A) 4 (B) 1 (C) 2 (D) 3
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